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2 years ago

Are AC and BE congruent? Explain.

Mathematics

1 answer:

garik1379 [7]2 years ago

7 0

They are not congruent because ac and be is when you con thing

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In a Calculus class, there are 11 freshman and 15 sophomores; 5 of the sophomores are females,

KATRIN_1 [288]

Answer:

61.5%

Step-by-step explanation:

Let's find all the demographics first:

Sophomores in the class(total 15):

Female: 5

Male : 10

Freshmen in the class(total 11):

Female: 3

Male: 8

There are 11 freshmen(male and female) and 5 female sophomores. Thus, the probability of choosing one of these 16 people in a class of 26 is 16/26 or 61.5%.

4 0

2 years ago

You call the pizza store and find out that each pizza has 12 slices. you expect 16 people to come, and you estimate each person

zysi [14]

Nx/y=z
3(16)/12=z
3x16=48/12=4
z=4

4 0

2 years ago

If ƒ(x) = -5n + 1 and g(x) = -6n + 2, find (ƒ + g)(-2).

Stels [109]

(f+g) (n) = (–5n +1 ) + (- 6n +2) = –11n +3

(f+g) (n) = –11n +3

(f+g) (–2) = – 11 (–2) +3 = 22 +3 = 25

I hope I helped you^_^

3 0

2 years ago

So I'm a little confused.?

juin [17]

All you have to do is multiply the area of the base times the length of the height, so:5 1/4*8=42
Answer:volume=42 cubic units

4 0

2 years ago

g A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 13

Luden [163]

Answer:

There is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

Step-by-step explanation:

A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°F.

So, Null hypothesis: $H_0:\mu \geq 135$

Alternate hypothesis : $H_a:\mu$

To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133°F.

x=133

n = 32

Population Standard deviation = $\sigma = 3.3^{\circ}F$

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}\\\\z=-3.428$

z=-3.43

Refer the z table for p value

p value = 0.0003

$\alpha = 0.10$

p value < α

So, we failed to accept null hypothesis

Hence there is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

6 0

2 years ago