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rjkz [21]
3 years ago
5

A mole is defined to be____particles of a substance.

Chemistry
1 answer:
Anika [276]3 years ago
6 0
A mole is defined to be like particales of a substance
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a gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressute of 2.1 atm. what is he partial pressure of gas
Igoryamba

The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.

The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an

individual gas in a mixture and n is total moles of the gas mixture. We

know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in

total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate

the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole

fraction of gas Y (x) and the total pressure (P) to calculate the

partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =

2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =

1.6 atm.

6 0
4 years ago
Read 2 more answers
The only way to convert between two substances is to use a _____ to _____ conversion.
kykrilka [37]

Mole to Mole.

Assuming you're referring to converting in general, there must always be a mole to mole conversion.

Gram to gram would be incorrect as you must have a molar conversion in order to do so.

Gram to mole would be incorrect because that would leave out molecular conversions which would require three steps rather than two.

Mole to molecule is incorrect as it leaves out grams, depending on the circumstances and equation provided.

Thus, through process of elimination, mole to mole is the correct answer.

Hope this helps!

4 0
3 years ago
What causes Brownian motion in colloids?
Ipatiy [6.2K]
Hey there!

Your answer is option A.

"Molecules of the dispersion medium colliding with dispersed phase particles" is what causes Brownian motion in colloids.

Hope this helps you.
Have a great day!
7 0
4 years ago
Read 2 more answers
Which area of science is considered the central science?
denis-greek [22]
Chemistry is the area considered the central science
7 0
3 years ago
Read 2 more answers
This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemin
azamat

Answer: your question is incomplete, please let me assume this to be your question.

This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemingly, spontaneously. Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions.

ReactionA: P i + glucose ⟶ glucose-6-phosphate + H 2 O Δ G = 13.8 kJ / mol Reaction

ReactionB: P i + fructose-6-phosphate ⟶ fructose-1,6-bisphosphate + H 2 O Δ G = 16.3 kJ / mol

Reaction C: ATP + H 2 O ⟶ ADP + P i Δ G = − 30.5 kJ / mol

1. Which of these reactions is (are) unfavorable? Select all that apply.

2. Which of these reactions can be coupled so that overall reaction is favorable? Select all that apply.

3. What is the net change in free energy if one selection from part (b) is coupled so that the overall reaction is favorable?

THE ANSWERS ARE AS FOLLOWS

1. REACTION B IS UNFAVOURABLE

2. REACTION A AND C CAN BE COUPLED SO THAT OVERALL REACTION IS FAVOURABLE

3. Since reaction b is coupled the net change becomes

13.8+16.3= 30.1

Therefore the net free change becomes

30.5 - 30.1 = 0.4kj/mol

Explanation: The glycolysis pathway

is to describe the oxidation of glucose to pyruvate, with the generation of ATP and NADH. This pathway is also known as the EMBDEN-MEYERHOF PATHWAY.

Reaction B is unfavorable because it is the conversation of glucose into an unstable form, that can be readily cleaved into 3-carbon units. The unfavorable fructose-6-phosphate is quickly consumed to favour the forward reaction.

Reaction A and Reaction C makes the overall reaction to be favoured, since the unfavorable reaction is reaction B, which is an intermediate reaction.

In calculation of net free energy the negative sign which shows Exothermic reaction is multiplied by a negative sign.

The final energy minus the initial energy. The reaction B is added to the initial energy because it is an intermediate reaction, and we were told that one part of it is coupled to the reaction.

Hope this has helped you to solve your question.

5 0
4 years ago
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