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Katena32 [7]
3 years ago
14

In a laboratory experiment you are given 46.1 grams of MgSO4 and asked to make a 1.20 M solution. The volume of your solution wi

ll be?
Question 7 options:

4625.4 L

0.459 L

0.319 L
Chemistry
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

0.319 L

Explanation:

M(MgSO4) = 120 g/mol

46.1 g * 1 mol/120 g = 0.384 mol MgSO4

0.384 mol * 1 L/1.20 mol = 0.319 L

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The pOH of a solution is 9.21. Calculate the hydrogen ion concentration of the solution. Be sure to report your answer to the co
11Alexandr11 [23.1K]

Answer:

[OH-] = 6.17 *10^-10

Explanation:

Step 1: Data given

pOH = 9.21

Step 2: Calculate [OH-]

pOH = -log [OH-] = 9.21

[OH-] = 10^-9.21

[OH-] = 6.17 *10^-10

Step 3: Check if it's correct

pOH + pH = 14

[H+]*[OH-] = 10^-14

pH = 14 - 9.21 = 4.79

[H+] = 10^-4.79

[H+] = 1.62 *10^-5

6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14

3 0
3 years ago
Describing Diffusion
yaroslaw [1]

Answer:

its the 3rd option.

the molecules move from region of higher concentration to a region of lower concentration.

Explanation:

please do give me brainliest if this helped you.

thank you and have a great day :D

3 0
3 years ago
Is PO4^-3 polar, non-polar, or ionic?
Gala2k [10]
The answer is PO4^-3 is non-polar.
8 0
3 years ago
If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
5 0
4 years ago
The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas is shown by which balanced chemical equation?
LekaFEV [45]
Know what decomposition is. The compound is "breaking down".

Di means 2 while, Tetra means 4.

First, we will simply follow the instructions and break down the compound as so: The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas

*Take into account that diatomic molecules (HNOFClBRI) will always have a subscript of 2

N
₂O₄⇒N₂+O₂

After breaking down the compound, we must now balance the equation.

To balance the equation, we must make sure that each element has the same amount of atoms.

Starting with compound at the left of the yield: N=2 and O=4
But, at the right of the yield: N=2 and O=2
We have now discovered that the oxygen gas is not balanced throughout the equation.

N₂O₄⇒N₂+2O₂

*We simply multiply the oxygen gas on the right of the equation by 2

After multiplying, on the right side of the equation, O=4. We now have a balanced equation because all elements have the same amount of atoms on each side.

So your final answer for this balanced decomposition chemical equation is: N₂O₄⇒N₂+O₂


6 0
4 years ago
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