1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ilia_Sergeevich [38]
3 years ago
14

An estate of $613,000 is left to three siblings. The eldest receives 2 times as much as the youngest. The middle sibling receive

s $16,000 more than the youngest.
How much did each receive?
The eldest sibling received $
the middle sibling received $
and the youngest sibling received$
Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

Eldest: $298500

Middle: $165250

Youngest: $149250

Explanation:

We can show the siblings like this:

e=2y                  (eldest)

m=16000+y       (middle)

To find the value of y, or the youngest sibling, we use an equation.

2y+16000+y+y=613000

Simplify:

4y+16000=613000

Subtract 16000 on both sides:

4y=597000

Divide both sides by 4:

y=149250

The youngest received $149250.

Knowing this, we can plug in the numbers into the original formulas:

e=2(149250)=298500                 ...or $298500

m=16000+149250=165250         ...or $165250

y=149250                                      ...or $149250

Add all those numbers up, and you reach $613000.

You might be interested in
PLS SOMEONE HELP ME ASAP
babymother [125]

Answer:

A. (2i)(8) = d. 16i

B. 16i³ = b. -16i

C. (2i)⁴ = a. 16

D. (2i)(8i) = c. -16

Step-by-step explanation:

A. Multiply 2i by 8 to get 16i, which corresponds to d.

B. The exponent is 3 more than a mulitple of 4 in 16i³, so the answer is negative. -16i corresponds to b.

C. (2i)⁴ has an exponent that is a multiple of 4, so the i isn't needed. 16 corresponds to a.

D. (2i)(8i) simplifies to 2(8) * i². The exponent is 2 more than a multiple of 4, so the answer is negative, without an i. -16 corresponds to c.

8 0
3 years ago
What is wrong with the following proof that for every integer n, there is an integer k such that n < k < n + 2? Suppose n
expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

4 0
3 years ago
Help with this question
Vikentia [17]

Answer:

60

Step-by-step explanation:

3 0
3 years ago
Find the inverse of h(x)
Brilliant_brown [7]

Answer:

f^{-1} (x) = \frac{x}{h}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the slope of the line passing throuon the points (-1,3) and (4,-7)
inn [45]

Answer:

-3.33333333333 or -10/3

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • if a given set has thirteen elements how many subsets have somewhere from four through eight elements
    8·1 answer
  • Partial quotient of 235 divided by 5
    5·2 answers
  • Hey guys how r u ? easy question
    10·1 answer
  • WX is parallel to YZ. If the measure of
    5·1 answer
  • PLS ANSWEE THIS AND IF YOU DO THANK YOU!!!
    13·1 answer
  • Whats this surface area?
    6·2 answers
  • Help me please. I really need it​
    9·2 answers
  • A scale drawing of a rectangular basketball court measures 7 inches long and 4 inches wide. If the scale used for the drawing is
    6·1 answer
  • PLZ HELPPPPPPP AND EXPLAIN BC I HAVE NO CLUE HOW TO DO THIS
    15·1 answer
  • I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!