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3 years ago

Which expressions are equivalent to 1.5?

Mathematics

1 answer:

3241004551 [841]3 years ago

6 0

Answer:

B and C

Step-by-step explanation:

We can just solve each to find which expressions are equal to 1.5.

A) 0.15 × 100 = 15

B) 15.0 ÷ 10 = 1.5

C) 0.15 × 10 = 1.5

D) 0.15 ÷ 10 = 0.015

E) 1.5 ÷ 100 = 0.015

From our results, we see that B and C are the only answers that equal 1.5.

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Use the distributive property to expand (simplify): 5(12mu - 7v)

mafiozo [28]

Answer:

Step-by-step explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>

3 0

3 years ago

You don’t have to answer both. Will give brainliest if you help.

SCORPION-xisa [38]

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Answer:

15) 27

16) 6144

Step-by-step explanation:

15) Jill's sequence is exponential:

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3 years ago

Solve using the quadratic formula <br> X^2=4x-8

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3 years ago

What percentage is 142-58

Misha Larkins [42]

SOLUTION:

Step 1 :

In this question, we are meant to find what percent of 142 is 58.

Step 2 :

We make the assumption that 142 is 100 % since it is our output value.

Step 3:

We next represent the value we see with x.

Step 4 :

From step 2, it follows that 100 % = 142.

Step 5 :

In the same vein, x % = 58.

Step 6 :

This gives us a pair of simple equations:

$\begin{gathered} 100\text{ \% = 142 ---- equ 1} \\ x\text{ \% = 58 }\ldots\ldots\ldots\ldots\text{ equ 2} \end{gathered}$

Step 7 :

By simply dividing equation 1 by equation 2 and

taking note of the fact that the Left-Hand Side of both equations have the same unit ( % ), we have that :

$\frac{100\text{ \%}}{x\text{ \%}}\text{ = }\frac{142}{58}$

Step 8 :

Taking the inverse ( or reciprocal ) of both sides yields:

$\frac{x\text{ \%}}{100\text{ \%}}\text{ = }\frac{58}{142}$ $\begin{gathered} x\text{ = }\frac{58\text{ x 100}}{142} \\ \text{x = }\frac{5800}{142} \\ x\text{ = 40.85\%} \end{gathered}$

CONCLUSION:

Therefore, 58 is 40.85 % of 142.

4 0

2 years ago

When an object is dropped on the moon, it travels approximately

kifflom [539]

Answer:

1.6 meters per second.

Step-by-step explanation:

We have been given an position function $P(t)=0.8t^{2}$ and we are asked to find the speed of the rock after 1 second.

Derivative of this function will give us speed function.

$S(t)=2\cdot 0.8\cdot t$

$S(t)=1.6\cdot t$

Now let us find derivative when t=1,

$S(1)=1.6\cdot 1=1.6$

Therefore, the speed of the rock after 1 second will be 1.6 meters per second.

7 0

3 years ago