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alina1380 [7]
3 years ago
6

Solve for y. 3y – 12 = –6                                           A. –54          B. 2          C. 18          D. –6

Mathematics
2 answers:
erastova [34]3 years ago
8 0
3y - 12 = -6
3y = 6                 | Add 12 to both sides
 y = 2                  | Divide by 3 on both sides


Answer: y = 2 (Answer B)
Ad libitum [116K]3 years ago
7 0
3y=-6+12. Combine like terms. So 3y=6 y=6/3. Divide. Y=2. So the answer will be B.2.
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Which relation is a function? {(–4, –6), (–3, –2), (1, –2), (1, 0)} {(–2, –12), (–2, 0), (–2, 4), (–2, 11)} {(0,1), (0, 2), (1,
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\{(8, 1), (4, 1), (0,1), (-15, 1)\}

Step-by-step explanation:

Given

\{(-4, -6), (-3, -2), (1, -2), (1, 0)\}

\{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}

\{(0,1), (0, 2), (1, 2), (1, 3)\}

\{(8, 1), (4, 1), (0,1), (-15, 1)\}

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Where x represents the range and y stands for the domain

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Start by splitting the relation into x and y columns

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(-4, -6)

(-3, -2)

(1, -2)

(1, 0)

Notice that the third and fourth relation has the same x value of 1;

<em>Hence, this is not a function</em>

B. \{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}

Start by splitting the relation into x and y columns

(x,y)

(-2, -12)

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(-2, 4)

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Notice that all relations has the same x value of -2;

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C. \{(0,1), (0, 2), (1, 2), (1, 3)\}

Start by splitting the relation into x and y columns

(x,y)

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(0, 2)

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Notice that the first and second relation has the same x value of 0 and the third and fourth relation has the same x value of 1;

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Start by splitting the relation into x and y columns

(x,y)

(8, 1)

(4, 1)

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Notice that relation has the unique x values of 8, 4, 0 and -15

<em>Hence, this relation is a function</em>

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