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Katen [24]
2 years ago
15

50 7 x + 22 x=? Please help

Mathematics
1 answer:
elena55 [62]2 years ago
3 0
X= 4

both of the angles are the same degrees so you figure out the difference between 50 and 22 and take that divided by 7 to get x

50-22

28/7

=4
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Choose Yes Or No To Tell if the fraction 4/9 will make each equation True.
BlackZzzverrR [31]

Answer:

true, true, false, true

Step-by-step explanation:

(4/9)*63=28

(4/9)*18=8

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(4/9)*36=16

5 0
2 years ago
Help solve<br> 1/2(X-34)=28+5X
IrinaK [193]

Answer:

x= -10 and true

Step-by-step explanation:

if you plug -10 in for x you get -22=-22 which makes it true

6 0
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When Marla rounded 19.95 to the nearest tenth, she found the number changed to 20.is this correct
dexar [7]
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3 years ago
Find the slope of the line that passes through the pair of points. F(–6, 8), P(–6, –5)
mariarad [96]
First, let's take a look at the formula to figure this out.

m = y2 - y1/x2 - x1

y2 would be -5, and y1 would be 8. -5 - 8 = -13.

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So, now we must divide -13 and -12, which results in 1 1/12. 
4 0
3 years ago
The graph of f(x) = 2x^2 + 20x + 48 is shown
Free_Kalibri [48]

Answer:

a) The equation in intercept form by factoring is (x+6)(x+4)

b) From the given graph x- intercepts are (-4,0) and (-6,0) and zeros (roots) of the function are -6 and -4.

c) The solutions of  2x^2+20x+48=0 is (x+6)(x+4)=0 that is x= -6 and x = -4.

Step-by-step explanation:

The given quadratic  equation is f(x)=2x^2+20x+48

Put the function f(x) = 0 , then f(x)=2x^2+20x+48=0

a) The equation in intercept form by factoring is ,

Consider the given function,

f(x)=2x^2+20x+48=0

\Rightarrow 2x^2+20x+48=0

taking 2 common, we get,

\Rightarrow 2(x^2+10x+24)=0

\Rightarrow x^2+10x+24=0

The above is a quadratic equation of the form ax^2+bx+c=0

Solving quadratic equation using middle term splitting method,

\Rightarrow x^2+6x+4x+24=0

\Rightarrow x(x+6)+4(x+6)=0

\Rightarrow (x+6)(x+4)=0

Thus, The equation in intercept form by factoring is (x+6)(x+4).

b) From the given graph x- intercepts are (-4,0) and (-6,0) .

Zeroes / roots of a function are those points where the value of the function is zero.

Put f(x) = 0  as solved above

that is (x+6)(x+4)=0

\Rightarrow (x+6)=0 or \Rightarrow (x+4)=0

\Rightarrow x=-6 or \Rightarrow x=-4

Thus, zeros (roots) of the function are -6 and -4.

For checking put x = -6 and -4 in the function we get f(x) =0 .

c) The solutions of  2x^2+20x+48=0 is (x+6)(x+4)=0 that is x= -6 and x = -4 as shown above.


8 0
3 years ago
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