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Y_Kistochka [10]
3 years ago
14

3 pizzas for $ 16.50 what is the unit rate for one pizza

Mathematics
2 answers:
o-na [289]3 years ago
8 0
The answer is 5.50$ you have to divide 16.50/ 3
Ganezh [65]3 years ago
4 0
$5.50 is your answer because its $16.50/3
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Check the picture below.  Count them up.

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7. Use the discriminant to determine the number of real solutions of the equation. 5x^2- 3x+1=0
MariettaO [177]

Answer:

c. None

Step-by-step explanation:

5x²- 3x+1=0         ax² + b + c = 0

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Can someone please help me?? :(
beks73 [17]

Answer:

y = 3x represents the graph. The point (4, 12) is on the line that is not shown on the graph.

Step-by-step explanation:

The equation of the line that  goes through origin= y = mx

Take any to points from the line

(0,0) & ( 2,6)

Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}=\dfrac{6-0}{2-0}=\dfrac{6}{2}=3

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y = 3x

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y = 3*4 = 12

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3 years ago
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3 years ago
The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area o
natita [175]

Answer:

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool = x

Then the length of a rectangular pool will be = 4x

Area\ of \ rectnagle= length\times breadth

                              =x\times4x\\ \\ =4x^{2}

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk = 4x+6+6=4x+12

Similarly, Combined width of pool and the sidewalk = x+6+6=x+12

Combined area of pool and the sidewalk = 1600

Combined\ lengthh\times Combined\ r=breadth=1600\\ \\ (4x+12)(x+12)=1600\\ \\ 4x(x+12)+12(x+12)=1600\\ \\ 4x^{2} +48x+12x+144=1600\\ \\ 4x^{2} +60x+144=1600

Subtracting both sides by 144

4x^{2} +60x=1456\\ \\ 4x^{2} +60x-1456=0\\ \\ Taking\ 4\ as\ common\\ \\ x^{2} +15x-364=0\\ \\ x^{2} +28x-13x-364=0\\ \\ x(x+28)-13(x+28)=0\\ \\ x+28=0,x-13=0\\ \\ x=-28,x=13

Since dimensions can never be in negative, hence x=13

Width of a rectangular pool = x = 13 feet

The length of a rectangular pool will be = 4x = 4\times13=52\ feet

Therefore, the dimensions of the pool are 52 feet by 13 feet.

8 0
3 years ago
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