Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.
Answer:
The answer is B (1 , 3) , (2 , 6) , (4 , 12) , (5 , 15)
Step-by-step explanation:
∵ X : 1 , 2 , 4 , 5
∵ Y : 3 , 6 , 12 , 15
∵ 2/6 = 1/3
∵ 4/12 = 1/3
∵ 5/15 = 1/3
∴ 1/3 = 2/6= 4/12 = 5/15 = 1/3 ⇒ all are proportion
∴ Answer B is in proportional relationship
Answer:
B. -6
Step-by-step explanation:
hope this helps!
A veriable = 1, use it as with pemdas
Answer:
164,160 just do 96% of it