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3 years ago

If the diameter is 20 cm what is the area based on pi

Mathematics

1 answer:

Anton [14]3 years ago

8 0

Answer:

$\Large \boxed{\mathrm{100\pi \ cm^2 }}$

Step-by-step explanation:

$\displaystyle area \ of \ circle \ = \ \pi (\frac{diameter}{2} )^2$

$\displaystyle A \ = \ \pi ( \frac{20}{2} )^2$

$\displaystyle A \ = \ \pi ( 10 )^2$

$\displaystyle A \ = \ 100\pi$

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Arturiano [62]

Answer:

Step-by-step explanation:

The original price of the jacket at the store is $50.

Evan has a coupon for 15$ off. This means that the amount that Evans will pay is the original price - 15% of the original price. It becomes

50 - (15/100 × 50) = 50 - 7.5 = $42.5

Max pays only 0.6 of the price because his father works at the store.

This means that the amount that Max will pay is 0.6 × the original price. It becomes

0.6 × 50 = $30

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3 years ago

Can someone help me with the First question ?

miskamm [114]

Answer:

Step-by-step explanation:

#1.

228 ÷ 6 = 38 in

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186 ÷ 3 = 62 ft

#3.

360 ÷ 8 = 45 yd

#4.

119 ÷ 7 = 17 ft

I hope I helped you.

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3 years ago

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Kate's dog was learning to balance a ball on his nose. The

Volgvan

Answer:

The answer is the first day.

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3 years ago

Write 3/5 as a % 60%

Alinara [238K]

Answer:

(3/5)× 100

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2 years ago

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An article gave the accompanying data on ultimate load (kN) for two different types of beams. Assuming the underlying distributi

krok68 [10]

Answer:

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

Step-by-step explanation:

We have to calculate a 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams.

The sample 1 (Fiberglass), of size n1=26 has a mean of 33.4 and a standard deviation of 2.2.

The sample 2 (Carbon), of size n2=26 has a mean of 42.8 and a standard deviation of 4.3.

The difference between sample means is Md=-9.4.

$M_d=M_1-M_2=33.4-42.8=-9.4$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{2.2^2}{26}+\dfrac{4.3^2}{26}}\\\\\\s_{M_d}=\sqrt{0.186+0.711}=\sqrt{0.897}=0.9473$

The critical t-value for a 99% confidence interval is t=2.678.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=2.678 \cdot 0.9473=2.537$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = -9.4-2.537=-11.937\\\\UL=M_d+t \cdot s_{M_d} = -9.4+2.537=-6.863$

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

8 0

4 years ago