Let a and b be integers and b>a, then we can say:
(b-a)/3=5 now multiply both sides by 3
b-a=15
b=15+a
So there are infinitely many pairs of integers that satisfy the conditions given in the problem. For any value a, b will be 15 units greater.
It would be the third. X+3=y
Each year, the current balance is multiplied by 1.07.
After 8 years, we'll have multiplied it by 1.07 eight times.
This can be written as

, which has a value of $34363.72, to the nearest cent.