Answer:
The percent chloride in the sample is 1.56%
Step-by-step explanation:
Hi there!
The molecular formula of silver chloride is AgCl. Its molar mass (the mass of a mol of AgCl) is 143.32 g/mol. Then the number of moles of AgCl obtained in the precipitated will be:
1.58 g · (1 mol/143.32 g) = 0.0110 mol
Then, since 1 mol AgCl contains 1 mol Cl⁻ (chloride), in the sample of compost there will be 0.0110 mol Cl⁻.
The mass of 0.0110 mol Cl⁻ is:
0.0110 mol Cl⁻ · (35.453 g /mol) = 0.390 g Chloride.
Then, the percent chloride in the sample will be:
0.390 g · (100 % / 25.0 g) = 1.56%
The percent chloride in the sample is 1.56%
Answer:
2088
Step-by-step explanation:
Answer:it’s a
Step-by-step explanation:
Step-by-step explanation:
<u>y</u> - <u>1</u> = <u>-</u><u>3</u>
x - 0 2
2y - 2 = -3x
2y = -3x + 2
Answer:
So then the correct answer is B. $200.
Step-by-step explanation:
Notation
Let X be the average contribution size before John makes his contribution.
Let Y be the total contribution size before John makes his contribution.
Let Z be John's contribution.
We know that for this case $ 75 represent the original average amount before the contribution with 50% increase so we can set up the following equation in order to find the original average amount
And solvong for X we got:
Now we can find the total contribution before the donation with the following proportion:
And then with the formula of average taking in count the 6 values we can find the size of donation Z like this:
So then the correct answer is B. $200.