Answer:
8^5^7
Step-by-step explanation:
Multiply the numbers:
<u>4</u>X^2 y^3 x <u>2</u>x^3 y^4
<u>8</u>^2 ^3 ^3 ^4
Combine Exponents:
8<u>^2</u> ^3 <u>^3</u> ^4
8<u>^5</u> ^3 ^4
8^5 <u>^3</u> <u>^4</u>
8^5 <u>^7</u>
Answer: (a) Yes. The table is a function.
<u>Step-by-step explanation:</u>
In order to be a function, there cannot be any duplicate x-values.
In the given table, each x-value is different so this IS a function.
A line parallel to your equation has the same slope, so it should be in the form:
y = (-3/2)x + b
To figure what "b" has to be, plug in the point (4,0) and solve:
0 = (-3/2)*4 + b
0 = -6 + b
6 = b
So the equation of the line is:
y = (-3/2)x + 6
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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