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Yakvenalex [24]
3 years ago
9

What number must you add to complete the square x^-8x=39

Mathematics
2 answers:
dem82 [27]3 years ago
6 0

Answer:

The number must be added to complete the square is  16

Step-by-step explanation:

It is given that,

x^2 - 8x = 39    ------(1)

The quadratic equation is of the form ax^2  + bx + c =0

To complete the square we have to add (b/2)^2 and subtract (b/2)^2

Therefore the eq (1) becomes

here b= -8, so we have to add (8/2)^2 = 4^2 = 16

Therefore the number is 16

<u>To find x</u>

x^2 - 8x  = 39

Add 16 to both sides

x^2 - 8x +16  = 39 + 16

(x - 4)^2 = 55

x - 4 = √55

x = √55 -4

notsponge [240]3 years ago
3 0

Answer:

Given equation: x^2-8x =39

when we complete the square , we take half of the value of 8 , then square it, and added to the left sides, we get;

x^2-8x+4^2 = 39 +4^2

∵8 is the value (\frac{8}{2})^2

Notice that, we add this both sides so that it maintains the equality.

then;

x^2-8x+4^2 = 39 +4^2

(x-4)^2 = 39 + 16   [ (a-b)^2 = a^2-2ab+b^2 ]

Simplify:

(x-4)^2 =55

The number must be added to complete the square is, 4^2 = 16



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