What number must you add to complete the square x^-8x=39
2 answers:
Answer:
The number must be added to complete the square is 16
Step-by-step explanation:
It is given that,
x^2 - 8x = 39 ------(1)
The quadratic equation is of the form ax^2 + bx + c =0
To complete the square we have to add (b/2)^2 and subtract (b/2)^2
Therefore the eq (1) becomes
here b= -8, so we have to add (8/2)^2 = 4^2 = 16
Therefore the number is 16
<u>To find x</u>
x^2 - 8x = 39
Add 16 to both sides
x^2 - 8x +16 = 39 + 16
(x - 4)^2 = 55
x - 4 = √55
x = √55 -4
Answer:
Given equation: 
when we complete the square , we take half of the value of 8 , then square it, and added to the left sides, we get;

∵8 is the value 
Notice that, we add this both sides so that it maintains the equality.
then;

[
]
Simplify:

The number must be added to complete the square is, 
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