(4x8) - (3x7) will give you what is showing of the red paper
The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.
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Question 1: a³ - 1000b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 1000 is the cube of 10
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(a - 10b) × (a² + 10ab + 100b²)
Question 2: 64a³ - 125b³
a³ - b³
= (a-b) × (a² +ab +b²)
- 64 is the cube of 4
- 125 is the cube of 5
- a³ is the cube of a¹
- b³ is the cube of b¹
So,
(4a - 5b) • (16a² + 20ab + 25b²)
Learn more about simplification:
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Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year.
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+
Year 3: 4800 * (1/4)³ = 75
+
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600
A worker can assemble 3 shelf units each hr. During the 5th hr...so the shift has been going on for 5 hrs...at 3 units per hr = (3 * 5) = 15 units assembled during the shift....and if there was 115 units in the warehouse, then that means before the shift, there were (115 - 15) = 100 units assembled <=
To find the surface area of the cube using the formula, you would substitute in 2 1/2 for the length of the side.
SA = 6 x 2.5 x 2.5
SA = 37.5 ft.²
You are finding the area of one face (2.5 x 2.5) and multiplying it by six because there are six groups of this.
