F(−2)=14. Explanation: substitute x=− 2 into f(x). f(−2)=(3×(−2)2)−(−2). ××=(3×4)+2=12+2=14 .
Answer:
third answer choice
Step-by-step explanation:
√ 98 square root is 7√2, a irrational number.
add 5
5+7√ 2, irrational
Answer:
The answer is C.
Step-by-step explanation:



The answer is C (I am assuming that it isn't 5/2).
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:
1 1/2
Step-by-step explanation:
1 1/2 + 3 1/2 = 5
6 1/2 - 5 =1 1/2