Answer: she put 0 In The box she would have a direct variation
Step-by-step explanation:
Y=5x-0
Lydia has zeroed, this expression means that it is a direct variation
Answer:
20.12 ft
Step-by-step explanation:
if you take 6^2 and subtract that from 21^2 then you will get your answer after finding the square root of the answer that the calculator gives you.
Answer:
Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)
- 6k + 7k = 1k = k
(7 - 6 = 1)
12r - 8 - 12 = 12r - 20
(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.
n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13
(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)
- 4x - 10x = 14x
(10 + 4 = 14)
- r - 10r = 11r
(r = 1 so 10 + 1 = 11)
How to get answer for number 1: | 4+2i |

How to get answer for number 2: | 5-i |

Number 3 how to get answer: | -3i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D0%2C%5C%3Ab%3D-3%5C%5C%3D%5Csqrt%7B0%5E2%2B%5Cleft%28-3%5Cright%29%5E2%7D%5C%5CRefine%5C%5C%3D%5Csqrt%7B9%7D%5C%5C%5Csqrt%7B9%7D%5C%5C%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A9%3D3%5E2%5C%5C%3D%5Csqrt%7B3%5E2%7D%5C%5C%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5Csqrt%7B3%5E2%7D%3D3%5C%5C%3D%203)
Answer:
They are congruent by SAS (Side Angle SIde) test or congruence criterion
Since,
In triangle ABD and triangle BCD
AB = BC (Given)
BD = DB(Common Side)
Angle ABD = Angle CBD
Therefore triangle ABD and triangle BCD by SAS (Side Angle SIde) test or congruence criterion