The factors of 7are -1 and 7 or 1 and -7, the factors of 14 are 1, 2, 7, and 14, or -1, -2, -7,-14. so the list of potential zeros are: 1/1, 1/2, 1/7, 1/14, 7/1,7/2, 7/7, 7/14, which can be simplified into 1, 1/2,1/7, 1/14, 7, 7/2
add the negative ones: -1, -1/2,-1/7, -1/14, -7, -7/2
I believe there are a total of 12 potential zeros
reference:
http://www.sparknotes.com/math/algebra2/polynomials/section4.rhtml
<span> 4x+7=5
subtract 7 on both sides
4x = -2
divide both sides by 4
x = -2/4
simplify
x = -1/2</span>
Answer:
yes
Step-by-step explanation:
by the side and letgh
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
(1)
= 
, substitute values , firstly calculating ∠ B
[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]
= 
( cross- multiply )
a sin53° = 18 sin78° ( divide both sides by sin53° )
a = 
≈ 22.0 ( to the nearest tenth )
(3)
= , substitute values
= 
( cross- multiply )
45 sinC = 35 sin134° ( divide both sides by 35 )
sinC = 
, then
∠ C = 
( ) ≈ 34.0° ( to the nearest tenth )
(5)
Calculate the measure of ∠ B
∠ B = 180° - (38 + 92)° = 180° - 130° = 50°
= , substitute values
= 
( cross- multiply )
BC sin50° = 10 sin38° ( divide both sides by sin50° )
BC = 
≈ 8.0 ( to the nearest tenth )
Since they want only the coordinates of the vertices. You only care about where the lines intersect, the greater than, less than signs are irrelevant.
Get each equation in 'y=mx+b' form
1) y = -x + 9
2) y = 2x-21
3) y = -4x +15
Now you can set any 2 equations equal to each other and solve for 'x'.
This will be the 'x' coordinate of the point where the 2 lines intersect.
You need 3 points, so you will need 3 different sets of 2 equations:
1) = 2)
2x -21 = -x+9
3x = 30
x = 10 -----> y = -(10)+9 = -1
1) = 3)
-x+9 = -4x+15
3x = 6
x = 2 -------> y = -(2) + 9 = 7
2) = 3)
2x - 21 = -4x+15
6x = 36
x = 6 ---------> y = 2(6) -21 = -9
Therefore the 3 intersecting points are:
(10,-1)
(2, 7)
(6, -9)
