Answer:
Part A: 81.5%
Part B: About 95% of the data lie between 53 and 65.
Step-by-step explanation:
Note: the percentages marked in red and blue never change
For Part A, we add the percentages that are between 53 and 62. So, 34% + 34% + 13.5% which is 81.5%
For Part B, we can look at this graph and seen that 95% of this data set lies between 53 and 65
Hope this is correct and of help!
Here is an example, if the graph hovers above the x-axis (k<0) then there will be no real solutions
119.5 would be the quotient
Answer:
Option C
Step-by-step explanation:
Assuming P represents the number of outcomes, n the number of competitors and r the number of places to be awarded....
There are 336 different possible ways for the winners to be chosen.
<u><em>Hope that helps!</em></u>
The perimeter of a rectangle is the sum of twice the length and twice the width. When a diagonal is drawn across the rectangle, two congruent triangles are formed. The legs of the triangle are the sides of the rectangle. Right triangles indicates that we can use the Pythagorean theorem. Let length = xLet width = y Set the equation based on what we know. 2x + 2y = 22 x + y = 11 eq1 x2 + y2 = [√65]2 eq2 We have two equations to work with. x + y = 11 eq1 x2 + y2 = 65 eq2 Substitute eq1 into eq2. From eq1, x = 11 - y x2 = (11 - y)2 x2 = (11 - y)(11 - y) x2 = 121 - 22y + y2 (121 - 22y + y2) + y2 = 65 121 - 22y + 2y2 = 65 2y2 - 22y + 56 = 0 2(y2 - 11y + 28) = 0 2(y - 7)(y - 4) = 0 y = 7 and y = 4 Substitute these y values into eq1 to solve for x. x = 11 - 7 and x = 11 - 4 x = 4 and x = 7 Each pair of solutions has the same dimensions. Shorter side = 4Longer side = 7