A rectangle is 5 times as long as it is wide. The perimeter is 70 cm. Find the dimensions of the rectangle. round to the nearest
2 answers:
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Answer:
The number of essay questions on the test were 9
Step-by-step explanation:
Given as :
Total number of questions in a test = 26
Total points for the 26 questions = 123
The point for each multiple choice questions = 3
The point for each essay questions = 8
Let The number of multiple choice questions = m
Let The number of essay questions = e
<u>Now, According to question</u>
Total number of questions in a test = number of multiple choice questions + number of essay questions
Or, m + e = 26 .....A
Again
Total points for the 26 questions = point for each multiple choice questions × number of multiple choice questions + point for each essay questions × number of essay questions
i.e 3 × m + 8 × e = 123
Or, 3 m + 8 e = 123 .......B
Solving the equation we get
8 × ( m + e ) - (3 m + 8 e) = 8 × 26 - 123
Or, 8 m + 8 e - 3 m - 8 e = 208 - 123
Or,(8 m - 3m) + (8 e - 8 e) = 85
Or, 5 m + 0 = 85
∴ m =
i.e m = 17
So,The number of multiple choice questions = m = 17
Put the value of m into eq A
∵ m + e = 26
Or, e = 26 - 17
i.e e = 9
So, The number of essay questions = e = 9
Hence, The number of essay questions on the test were 9 . Answer
Answer:
(x-2)(x+3)(x+6)
Step-by-step explanation:
Given the polynomial function p(x)=x^3+7x^2-36
We are to write it as a product of its linear factor
Assuming the value of x that will make the polynomial p(x) to be zero
Let x = 2
P(2) = 2³+7(2)²-36
P(2) = 8+7(4)-36
P(2) = 8+28-36
P(2) = 0
Since p(2) = 0 hence x-2 is one of the linear factors
Also assume x = -3
P(-3) = (-3)³+7(-3)²-36
P(-3) = -27+7(9)-36
P(-3) = -27+63-36
P(-3) = 36-36
P(-3) = 0
Since p(-3) = 0, hence x+3 is also a factor
The two linear pair are (x-2)(x+3)
(x-2)(x+3) = x²+3x-2x-6
(x-2)(x+3) = x²+x-6
To get the third linear function, we will divide x^3+7x^2-36 by x²+x-6 as shown in the attachment.
x^3+7x^2-36/x²+x-6 = x+6
Hence the third linear factor is x+6
x^3+7x^2-36 = (x-2)(x+3)(x+6)
