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TEA [102]
3 years ago
13

A rectangle is 5 times as long as it is wide. The perimeter is 70 cm. Find the dimensions of the rectangle. round to the nearest

tenth if neccasary.
Mathematics
2 answers:
torisob [31]3 years ago
7 0
L=5W

P=2(L+W), using L found above in this equation gives us:

P=2(5W+W)

P=2(6W)

P=12W

W=P/12, we are told that P=70

W=70/12

W=5 5/6, and since L=5W

L=25+25/6

L=29 1/6

So the length is 29 1/6 cm and the width is 5 5/6 cm.  If you wish to round to nearest tenths, length is 29.2 cm and width is 5.83 cm.
kirill [66]3 years ago
3 0
Lrspow is correct, good work
You might be interested in
Question
Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) =  (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

          25 ft =  (1/2)*(32.17 ft/s^2)*t^2

         2*25ft = (32.17 ft/s^2)*t^2

           50ft =  (32.17 ft/s^2)*t^2

         √( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0
3 years ago
Which of the choices below is not a possible correlation coefficient?
fiasKO [112]

Answer:

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

Step-by-step explanation:

The correlation coefficient is a measure of dispersion and is a value between -1 and 1, and is defined as:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

8 0
3 years ago
Sue bought two pairs of jeans and a belt that costs $6.95 the tax on the items was $5.85 sue pay the cashier $70 how much money
yaroslaw [1]
<span>cost of two pair of jeans- $55
   cost of belt-$ 5.85
   tax- $5.85
       total bill- $67.8
       as sue paid $70 to the cashier for the bill amount so she will get $2.2 change in return.</span>
6 0
3 years ago
Round the decimal 7.86 ?
solniwko [45]

Answer:

The answer would be 9.0.

Step-by-step explanation:

Hope it help you.

8 0
2 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
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