It would be web plato because thats how it is, i think.
(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Answer:
David gets 28 more than Dan
Step-by-step explanation:
Jim: Dan : David: total
3 : 1 : 5 : 3+1+5 = 9
Jim gets 21
21/3 = 7
Multiply each number by 7
Jim: Dan : David: total
3*7 : 1*7 : 5 *7 : 9*7
21 : 7 : 35 : 63
David has 35 and Dan has 7
35-7 = 28
David gets 28 more than Dan
Answer:
10
Step-by-step explanation:
-3x+7x-8=34+9x-2
(Combine like terms)
4x-8=32
(Add 8 to each side)
4x=40
(Divide by 4)
X=10
Answer:
4/9 is the answer
Hope it correct and it helps
