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Lorico [155]
3 years ago
6

I’ll really appreciate it if you help me out with this one .

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

the answer is d

Step-by-step explanation:

because i said so

but also i figured it out

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1+10=10<br> 2+20 =20<br> 3+30=28<br> 4+40=32<br> 5+50=28<br> 6+60=?
aniked [119]

Hey! Your answer is here!

The answer to the problem is 10.

Hope this helps! :)

6 0
2 years ago
Please please please I'm begging you help me find the y intercept for these I will give brainliest
konstantin123 [22]

Answer:

1. (2+2)/(-3+4)= 4/1= 4

y + 2 = 4(x + 4)

y + 2 = 4x + 16

y = 4x + 14 y-intercept:(0,14)

2. (0+5)/(-1+2)= 5/1= 5

y + 5 = 5(x + 1)

y + 5 = 5x + 5

y = 5x

y-intercept (0,0)

3. (-1+1)/(-5-3)= 0/-8= 0

y + 1 = 0(x - 3)

y + 1 = 0

y= -1

6 0
3 years ago
Maryland had $(62xsquared + x - 4) on mondays she spent $(11x squared - 33) on a pair of gloves how much money did she have left
Anton [14]

Answer:

$( 51x^2 + x + 29).

Step-by-step explanation:

Amount she had left = original amount - amount spent on the gloves

=  62x^2 + x - 4 - (11x^2 - 33)   (note we place the amount spent on gloves in parentheses because we have to subtract the whole amount)

Now we distribute the negative over the parentheses:

= 62x^2 + x - 4 - 11x^2 + 33     ( note - 33 becomes -33*-1 = +33)

Now simplifying like terms:

= 51x^2 + x + 29  (answer).

7 0
3 years ago
What equation shows the relationship between the profit function, cost function and revenue function?
vlabodo [156]

Profit function - Cost function = Revenue function

6 0
3 years ago
Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides? It would be a great he
bija089 [108]

Answer: AC= 10 cm and CE= 5 cm


Step-by-step explanation:

In the given picture, Δ ADE is a right triangle

∴ By Pythagoras theorem,

AD^2+DE^2=AE^2\\\Rightarrow\ (8+4)^2+9^2=AE^2\\\Rightarrow\ AE^2=12^2+9^2\\\Rightarrow\ AE^2=144+81=225\\\Rightarrow\ AE=15\ cm

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

\frac{AB}{AC}=\frac{AD}{AE}\\\Rightarrow\frac{8}{AC}=\frac{12}{15}\\\Rightarrow\ AC=\frac{8\times15}{12}\\\Rightarrow\ AC=10\ cm

Now, AE=AC+CE

⇒CE=AE-AC

⇒CE=15-10=5 cm


4 0
3 years ago
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