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3 years ago

Y=99.99+23.75(x-1) as a Y=ax+b equation

Mathematics

1 answer:

Hatshy [7]3 years ago

6 0

Answer:

$y = 23.75x + 76.24$

Step-by-step explanation:

We want to rewrite

$y = 99.99 + 23.75(x - 1)$

in the form

$y = ax + b$

We expand to get:

$y = 99.99 + 23.75x - 23.75$

Regroup similar terms:

$y = 23.75x - 23.75 + 99.99$

Simplify:

$y = 23.75x + 76.24$

This is now of the form

$y = ax + b$

where a=23.75 and b=76.24

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3 years ago

ASAP please.<br> Not understanding

vivado [14]

Bryan has 180 feet of fencing. he use the wall for one side of fencing

So he has to fence only 3 sides

he has to fence bottom side + left side+ right side of the wall

Let x be the width of the garden

Let y be the length

Perimeter of the garden = length + width + width

180 = y +x +x

180 = y+2x

so y = 180 - 2x

(a) Area of rectangle = Length * width

Area = y * x

Area = (180 -2x)* x

so area of the garden = -2x^2 +180x

(b)To find dimension to create largest are we find x coordinate of the vertex

formula is $x= \frac{-b}{2a}$

a= -2 and b = +180

$x= \frac{-180}{2(-2)}= 45$

So width = 45

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Length = 90 feet

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6 0

3 years ago

A restaurant sold 35 burgers with cheese if the ratio of the burgers sold with cheese compared to without cheese was 7 : 3 how m

Montano1993 [528]

We need to write a proportion to solve this

7/3=35/x

105=7x

divide each side by 7

15=x so, there were 15 burgers without cheese.

We could add the cheese burgers 35 to burgers without cheese 15

35+15=50 burgers were sold.

7 0

3 years ago

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earnstyle [38]

Answer:

6/8

just add the fractions together after making the bottom the same

4 0

3 years ago

Read 2 more answers

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th

finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0

3 years ago