Given:
Growth rate = 30% decrease
To find:
The growth factor associated with the given growth rate.
Solution:
The general exponential function is:


Where, a is the initial value, r is the growth rate in decimal and
is the growth factor.
It is given that the growth rate is 30% decrease. So,



Now,




Therefore, the growth factor is 0.7.
Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

Answer:
ITs C One solution
Step-by-step explanation:
Two sides are not equal.
Answer:
x = 5 only
≡ On a graph, the point touches (5, 0), making <em>x</em> equal to 0.
≡ In other words, you must replace <em>y</em> with <em>0</em> to solve for <em>x. </em>There is no <em>y</em> term in this problem, so you must determine <em>y</em> by separating the coefficients into groups and determining each part.
The answer is C it will be congruent to another angle