Answer:
- one orange costs $0.35 and one grapefruit costs $0.45
Step-by-step explanation:
<em>let grapefruits be g , let oranges be o</em>
so first equation:
→2g + 3o = $1.95
→g = ($1.95 - 3o)/2
so second equation:
→ 3g + 2o = $2.05
→ g = ($2.05 - 2o)/3
Solving simultaneously:
→ ($2.05 - 2o)/3 = ($1.95 - 3o)/2
→ 2($2.05 - 2o) = 3($1.95 - 3o)
→ 4.1 - 4o = 5.85 - 9o
→ - 4o + 9o = 5.85 - 4.1
→ 5o = 1.75
→ o = $0.35
Therefore one orange costs $0.35
Then one grapefruit costs g → ($1.95 - 3o)/2
→ g = ($1.95 - 3(0.35))/2
→ g = 0.45
Therefore one grapefruit costs $0.45
Answer:
B.
Step-by-step explanation:
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
Answer: ,
Explanation:2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) =
sin(q) =
Now, we know that:
sin (45) =
From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to
or q = 270 + 45 = 315° which is equivalent to
Hope this helps :)