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2 years ago

Find the inequality represented by the graph

Mathematics

1 answer:

leva [86]2 years ago

6 0

Answer: y<x-1

Step-by-step explanation:

So first we have to find the blue line. y=mx+b is the equation. For slope it is 0--1 which is 1 and 1-0 which is 1 so the slope is just one or x now we need to find the y intercept which is just -1. So y<(is less than)x-1! Hope this helps :)

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Step-by-step explanation:

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Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$

Step 3: Find Particular Solution

Substitute in point [Function]: $\displaystyle 18 = \frac{0^2}{16} + C$
Simplify: $\displaystyle 18 = 0 + C$
Add: $\displaystyle 18 = C$
Rewrite: $\displaystyle C = 18$
Substitute in C [Function]: $\displaystyle y = \frac{t^2}{16} + 18$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

4 0

2 years ago

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MArishka [77]

Answer:

im just answering because my name is marcus.

Step-by-step explanation:

-56.3015% change

56.3015% decrease

8 0

2 years ago

30 Points!!

neonofarm [45]

Answer:

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Step-by-step explanation:

The matrix equation ...

AX = B

is solved by left-multiplying by the inverse of A:

A⁻¹AX = A⁻¹B

IX = A⁻¹B . . . . . the result of multiplying A⁻¹A is the identity matrix

X = A⁻¹B . . . . . B needs to be multiplied by the inverse matrix

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2 years ago

Find the inequality represented by the graph ​

Find the inequality represented by the graph