Can i pls get help with this homework question if you get it right i will give you branlest

Which of the following illustrates the truth value of the given conditional statement?

bazaltina [42]

Given p: 10 < 7, clearly p is false and ~p is true. Also, given q: 10 < 5, clearly q is false and ~q is true.

Thus, the truth value of the conditional statement ~p → ~q is <span>T T → T.</span>

6 0

2 years ago

A rectangle has a length two times the width. Describe how you would find the

IRINA_888 [86]

Answer:

perimeter = 6w

area = 2w^2

Step-by-step explanation:

we can use the variable w for width, and 2w for length perimeter would be width + width + length + length, or 6w

area is width x length or 2w^2

4 0

2 years ago

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PLEASE HELP ASAP!!!!

Bogdan [553]

Step-by-step explanation:

I think C. objects color and texture distributed thoughout the photo

6 0

3 years ago

Solve for x 6(4x+1)=78

FromTheMoon [43]

Answer:

x=3

Step-by-step explanation:

5 0

2 years ago

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A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

2 years ago