<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
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<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
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<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
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<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
Hello from MrBillDoesMath!
Answer: x = -1
Discussion:
Let x be the unknown integer. Then
5
x^2 + 3x = 2 or
5x^2 + 3x -2 = 0 or (factoring)
(x+1) ( 5x -2) = 0
so x = -1 (the other value of x, +2/5, is not an integer)
Thank you,
MrB
I believe the answer would be c. $499.75. If you take (360.75-82.75)/(6-2) you get 278/4 which is dollars/hour, and that =69.5 so the rate of increase is $69.50 per hour, therefore if 6 hours produced $360.75 then you +$69.50•2(hours) and get $499.75
200 x 9
900 x 2
600 x 3
450 x 4
360 x 5
300 x 6
225 x 8
Well nine times 199 is 1,791but im not sure if thats what its asking
