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1 year ago

An acute triangle has sides measuring 10cm and 16cm. The length of the third side is unknown.

Mathematics

1 answer:

Mariulka [41]1 year ago

8 0

What best describes the range of possible values for the third side of the triangle are

If the 3rd side is less than 6, it could never reach between the ends of the 10 and the 16.
If the 3rd side is more than 26, then the 10 and the 26 could never reach its ends.

This is further explained below.

<h3>What is the range?</h3>

Generally, After removing the sample maximum and lowest, we get the range of the data set. It shares the same measurement systems as the data.

In conclusion, Choose the options that best characterize the interval across which the third side may take on a value;

When the 10 and 16 are placed end to end, the third side can never be shorter than 6.

If the sum of the 10 and the 26 is more than the third side's value, then the 10 and the 26 will never sum to the side's value.

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Llana [10]

Answer:

(a) Equations for both

$y = 500 + 12x$ --- lifeguard

$y = 15x$ --- camp counselor

(b) Total pay for 5 days

Lifeguard pays $800

Camp counselor pays $375

(c) Which pays more

Lifeguard job pays more

Step-by-step explanation:

Let

$x \to hours$

$y \to total\ pay$

Given

Lifeguard job

$Signing\ bonus = \$500$

$Rate = \$12/hr$

Camp counselor job

$Signing\ bonus =\$0$

$Rate = \$15/hr$

Solving (a): The equation for both

The total pay for each job is calculated as:

Total Pay = Signing Bonus + Rate * Hours

So, we have:

Lifeguard

$y = 500 + 12*x$

$y = 500 + 12x$

Camp counselor

$y = 0 + 15 * x$

$y = 15x$

Solving (b): Total pay for 5 days

First, we calculate the total hours worked in 5 days

$x = 5hrs/day * 5days$

$x = 25hrs$

So, the pay for each is:

$y = 500 + 12x$

$y =500 + 12*25$

$y =800$ --- Lifeguard

$y = 15x$

$y = 15 * 25$

$y = 375$ --- camp counselor

Solving (c): Which job pays more

By comparing the solution in (b)

$800 > 375$

<em>Hence, lifeguard job pays more</em>

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3 years ago

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zloy xaker [14]

Answer:

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$f(n) = 5 \times 4 ^{n - 1}$

Step-by-step explanation:

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3 years ago

Given: ΔABC; a= 10; b = 4, and c = 11. Find the measurement of ∠B to the nearest tenth of a degree.

AleksAgata [21]

Use the Cosine Rule to find this

cos <B = [b^2 - a^2 - c^2] / -2ac

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