Use height over shadow and solve for x
5.5 X
---- = ----
8 33
Find a common denominator and you're all set
Answer:
see explanation
Step-by-step explanation:
2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.
6
BE × ED = AE × CE , that is
10 × 3x = 12(2x + 1) ← distribute parenthesis by 12
30x = 24x + 12 ( subtract 24x from both sides )
6x = 12 ( divide both sides by 6 )
x = 2
then
ED = 3X = 3(2) = 6
7
RJ × JP = SJ × JQ , that is
6 × 3x = 4(4x + 1) ← distribute parenthesis by 4
18x = 16x + 4 ( subtract 16x from both sides )
2x = 4 ( divide both sides by 2 )
x = 2
then
RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12
Answer:
5
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given:</u>
Base = b = 2 in.
Perpendicular = a = 2 in.
<u>Required:</u>
Hypotenuse = c = ?
<u>Formula:</u>
(Pythagoras Theorem)
<u>Solution:</u>
c² = (2)² + (2)²
c² = 4 + 4
c² = 8
Taking sqrt on both sides
c = 2.8 in.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
