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9966 [12]
3 years ago
14

The coordinate plane below represents a city. Points A through F are schools in the city.

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
PART A

Refer to the diagram below for the region that only has point C and F inside the shaded region

The three inequalities can be:
y ≥ 1
x ≥ 1
y ≤ -x + 8
---------------------------------------------------------------------------------------------------------

PART B

Coordinate of C is (2, 2)
Coordinate of F is (3, 4)

For the inequality y ≥ 1, the y-coordinate of both point C and F are more than 1

For the inequality x ≥ 1, the x-coordinate of both point C and F are more than 1

For the inequality y ≤ -x + 8
Start with point C, we substitute the x-coordinate = 2 and check whether -x + 8 is indeed more than y
-x + 8 = -(2) + 8 = 6 and 6 ≥ 2

Point D (3, 4), substituting x = 3
-x + 8 = -(3) + 8 = 5 and 5 ≥ 4

So point C and F are solutions to the inequalities
--------------------------------------------------------------------------------------------------------------

PART C

Refer to the second diagram below, the points below the line -2x + 2 are A., B, and D. We choose the point below the line because the inequality want 'y' to be less than -2x + 2


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Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

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a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

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b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

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x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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