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9966 [12]
3 years ago
14

The coordinate plane below represents a city. Points A through F are schools in the city.

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
PART A

Refer to the diagram below for the region that only has point C and F inside the shaded region

The three inequalities can be:
y ≥ 1
x ≥ 1
y ≤ -x + 8
---------------------------------------------------------------------------------------------------------

PART B

Coordinate of C is (2, 2)
Coordinate of F is (3, 4)

For the inequality y ≥ 1, the y-coordinate of both point C and F are more than 1

For the inequality x ≥ 1, the x-coordinate of both point C and F are more than 1

For the inequality y ≤ -x + 8
Start with point C, we substitute the x-coordinate = 2 and check whether -x + 8 is indeed more than y
-x + 8 = -(2) + 8 = 6 and 6 ≥ 2

Point D (3, 4), substituting x = 3
-x + 8 = -(3) + 8 = 5 and 5 ≥ 4

So point C and F are solutions to the inequalities
--------------------------------------------------------------------------------------------------------------

PART C

Refer to the second diagram below, the points below the line -2x + 2 are A., B, and D. We choose the point below the line because the inequality want 'y' to be less than -2x + 2


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Can someone help me with this math hw ​
AveGali [126]

Answer:

Step-by-step explanation:

F(x) = x² - 2x + 1

      = (x - 1)²

By comparing this equation with the vertex form of the quadratic equation,

y = (x - h)² + k

Here, (h, k) is the vertex

Vertex of the parabola → (1, 0)

x-intercepts → (x - 1)² = 0

                       x = 1

y-intercepts → y = (0 - 1)²

                       y = 1

Now we can draw the graph of the given function,

From this graph,

As x → 0,

\lim_{x \to 0^{-}} (x-1)^2=1

\lim_{x \to 0^{+}} (x-1)^2=1

f(0) = (0 - 1)²

     = 1

Since, \lim_{x \to 0^{-}} (x-1)^2=\lim_{x \to 0^{+}} (x-1)^2=1

Therefore, given function is continuous at x = 0.

8 0
3 years ago
Susan is making 8 casseroles. She uses 9 cans of beans. Each can is 16 oz. If she divides the beans equally among casseroles? Sh
belka [17]

Answer:

The correct answer will be 18

Step-by-step explanation:

First mutiply your object of the question which is 9 times 16 then make sure you have the right answer then divide it by 8 and 144 the answer you got, and you get 18

3 0
2 years ago
What is the total cost of a $28 pair of jeans if the sales tax is 7.5%?
KatRina [158]

Answer:

30.10

Step-by-step explanation:

First find the amount of tax

28 * 7.5%

28 * .075

2.10

Add this to the price of the pants

28+2.10 =30.10

8 0
3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
what are the explicit equation and domain for a geometric sequence with a first term of 5 and a second term of -10
OleMash [197]
a_1=5;\ a_2=-10;\ r=a_2:a_2\to r=-10:5=-2\\\\a_n=a_1r^{n-1}\\\\\boxed{a_n=5\cdot(-2)^{n-1}}
6 0
3 years ago
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