The coordinate plane below represents a city. Points A through F are schools in the city.
1 answer:
PART A
Refer to the diagram below for the region that only has point C and F inside the shaded region
The three inequalities can be:
y ≥ 1
x ≥ 1
y ≤ -x + 8
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PART B
Coordinate of C is (2, 2)
Coordinate of F is (3, 4)
For the inequality y ≥ 1, the y-coordinate of both point C and F are more than 1
For the inequality x ≥ 1, the x-coordinate of both point C and F are more than 1
For the inequality y ≤ -x + 8
Start with point C, we substitute the x-coordinate = 2 and check whether -x + 8 is indeed more than y
-x + 8 = -(2) + 8 = 6 and 6 ≥ 2
Point D (3, 4), substituting x = 3
-x + 8 = -(3) + 8 = 5 and 5 ≥ 4
So point C and F are solutions to the inequalities
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PART C
Refer to the second diagram below, the points below the line -2x + 2 are A., B, and D. We choose the point below the line because the inequality want 'y' to be less than -2x + 2
Refer to the diagram below for the region that only has point C and F inside the shaded region
The three inequalities can be:
y ≥ 1
x ≥ 1
y ≤ -x + 8
---------------------------------------------------------------------------------------------------------
PART B
Coordinate of C is (2, 2)
Coordinate of F is (3, 4)
For the inequality y ≥ 1, the y-coordinate of both point C and F are more than 1
For the inequality x ≥ 1, the x-coordinate of both point C and F are more than 1
For the inequality y ≤ -x + 8
Start with point C, we substitute the x-coordinate = 2 and check whether -x + 8 is indeed more than y
-x + 8 = -(2) + 8 = 6 and 6 ≥ 2
Point D (3, 4), substituting x = 3
-x + 8 = -(3) + 8 = 5 and 5 ≥ 4
So point C and F are solutions to the inequalities
--------------------------------------------------------------------------------------------------------------
PART C
Refer to the second diagram below, the points below the line -2x + 2 are A., B, and D. We choose the point below the line because the inequality want 'y' to be less than -2x + 2
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