Answer:
see below
Step-by-step explanation: 5 27 7 16
area = 1/2 bh
height of a triangle is 7 ft more than its base
base = b
height = b + 7
area = 30
area = 1/2 b(h)
30 = 1/2 b(b + 7)
30 = 0.5(b²+ 7b)
30 = 1/2 b²+ 3.5b solve for b
1/2 b²+ 3.5b = 30
1/2 b²+ 3.5b - 30 = 0
b²+ 7b - 60 = 0 factor
(b +12)(b - 5) = 0 when b = -12 or 5 base length can't be negative
b = base = 5
area = 1/2 bh 1/2×2(9) = 9
area = 1/2 bh 1/2×5(12) = 60
area = 1/2 bh 1/2×9(16) = 56
area = 1/2 bh 1/2×12(19) = 114
Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
D--because it has y^2 in the equation and to isolate y you have to take the square root, the graph is going to be curved rather than linear.
