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2 years ago

HELPPPP FIND THE AREA

Mathematics

2 answers:

never [62]2 years ago

7 0

Answer:

Area = 24

Step-by-step explanation:

Work and explanation ~

GuDViN [60]2 years ago

5 0

you can just split the figure in 2 separate figures and them add the areas:

area rec. 1:

3m×3m= 9m²

area rec. 2:

3m× (2m+3m)

= 3m×5m

=15m²

total area:

9m²+15m²= 24m²

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What is the value of x?<br> X= 10^2 + 8^2

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$\: \: \: \: \: \: \: \: \: x = {10}^{2} + {8}^{2} \\ x = 164$

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2 years ago

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Given the function, f(x)=[square root] x+3-2 , calculate the average rate of change between x=6 and x=13.

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F(6) = 3-2 = 1
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3 years ago

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abbie spent 5/8 of her money and saved the rest. if she spent 45,how much money did she have at first?

algol13

$72

<h3>Further explanation</h3>

<u>Given:</u>

Abbie spent ⁵/₈ of her money and saved the rest.

She spent $45.

<u>Question:</u>

How much money did she have at first?

<u>The Process:</u>

The meaning of "Abbie spent ⁵/₈ of her money" is that she has spent 5 of the 8 parts of the money she had at first.

Let us make a pattern of 8 units for the amount of money that Abbie had at first.

$\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}$

Since Abbie spent ⁵/₈ of her money, then we create a pattern of 5 units containing $9 each. Recall that $\boxed{\$ 45 \div 5 = \$ 9}$

$\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 45$

From the pattern above, we can see that $\boxed{ \ 1 \ unit = \$ 9 \ }.$

Let us calculate how much money Abbie had at first.

$\boxed{ \ 1 \ unit = \$ 9 \ }$

$\boxed{ \ 8 \ unit = \ ? \ }$

$\boxed{ \ 8 \times \$ 9 = \$ 72 \ }$

Thus, the money Abbie had at first is $72.

The complete pattern of Abbie's initial money is as follows:

$\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 72$

- - - - - - - - - -

<u>Quick Steps:</u>

Let M as Abbie's initial money.

$\boxed{ \ \frac{5}{8} \times M = \$ 45 \ }$

Both sides are multiplied by ⁸/₅ so that M is the subject alone on the left side.

$\boxed{ \ M = \frac{8}{5} \times \$ 45 \ }$

We crossed out 5 and 45.

$\boxed{ \ M = 8 \times \$ 9 \ }$

$\boxed{ \ M = \$ 72 \ }$

Thus, the money Abbie had at first is $72.

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Keywords: Abbie, spent 5/8 of her money, saved the rest, $45, $72, how much money, she have at first, the pattern

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4 years ago

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Mr. Akika has 30 24-cent and 33-cent stamps all told. The stamps are worth $8.91. How many of each kind of stamp does he have?

riadik2000 [5.3K]

Answer:

24-cent: 11
33-cent: 19

Step-by-step explanation:

I find it easiest to solve these using the variable to represent the number of the most-expensive item. Let x represent the number of 33-cent stamps. Then the total value (in cents) is ...

33x +24(30 -x) = 891

9x = 171 . . . . . . . . . . . . . subtract 24(30), collect terms

x = 19 . . . . . . . . . . . . divide by 9

30-x = 11 . . . . . . . find the number of 24-cent stamps

Mr. Akika had 11 24-cent stamps and 19 33-cent stamps.

_____

<em>Additional comment</em>

You seem to have several of these to solve. They all have a similar solution.

If we let x represent the number of higher-value items, N, the total number of items, V the total value, and v1 and v2 the individual values (v2 > v1), the equation is ...

v2(x) +v1(N -x) = V

x(v2 -v1) = V -v1·N

x = (V -v1·N)/(v2 -v1) . . . . generic solution

Using this formula in the problem here, we find ...

x = (891 -24(30))/(33 -24) = 171/9 = 19 . . . as above

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