HELPPPP FIND THE AREA
2 answers:
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<h2>Answer:</h2>
1. A coin is tossed four times. What is the probability of getting four heads?
Each toss has a 1/2 chance of getting a head.
So the chance of getting all four heads can be calculated as :
2. A coin is tossed four times. What is the probability of getting two heads?
Each toss can have 2 results, so 4 flips will have or 16 results.
Getting two heads means getting two tails also. So, we can get the number of times two heads come = = 6
We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}
So, the required probability is : 6/16 or 3/8.
3. Not getting two heads means getting 3 tails and 1 head or all tails.
Probability of having all tails =
Probability of one head(1st trial) and three tails = 1/16
Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16
Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16
Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16
So, the total probability showing only one or none head and at least three tails =
Answer:
∠J = 60°
Step-by-step explanation:
The Law of Cosines tells you ...
j² = k² +l² -2kl·cos(J)
Solving for J gives ...
J = arccos((k² +l² -j²)/(2kl))
J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)
J = 60°
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<em>Additional comment</em>
It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.
