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erica [24]
3 years ago
5

​(4x2−2x+28​)+​(4x2+4x−55​)

Mathematics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

\boxed{ \bold{ \boxed{ \sf{8 {x}^{2}  + 2x - 27}}}}

Step-by-step explanation:

\sf{(4 {x}^{2}  - 2x + 28) + (4 {x}^{2}  + 4x - 55)}

When there is a ( + ) in front of an parentheses in an expression, there is no need to change the sign of each term in the expression. That means , the expression remains the same. Just, remove the unnecessary parentheses

\dashrightarrow{ \sf{4 {x}^{2}  - 2x + 28 + 4 {x}^{2}  + 4x - 55}}

Collect like terms and simplify

\dashrightarrow{ \sf{4 {x}^{2}  + 4 {x}^{2}  - 2x + 4x + 28 - 55}}

\dashrightarrow{ \sf{8 {x}^{2}  + 2x + 28 - 55}}

The negative and positive integers are always subtracted but possess the sign of the bigger integer.

\dashrightarrow{ \sf{8 {x}^{2}  + 2x - 27}}

Hope I helped!

Best regards! :D

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