Question

​(4x2−2x+28​)+​(4x2+4x−55​)

Answer 1

Answer:

$\boxed{ \bold{ \boxed{ \sf{8 {x}^{2} + 2x - 27}}}}$

Step-by-step explanation:

$\sf{(4 {x}^{2} - 2x + 28) + (4 {x}^{2} + 4x - 55)}$

When there is a ( + ) in front of an parentheses in an expression, there is no need to change the sign of each term in the expression. That means , the expression remains the same. Just, remove the unnecessary parentheses

$\dashrightarrow{ \sf{4 {x}^{2} - 2x + 28 + 4 {x}^{2} + 4x - 55}}$

Collect like terms and simplify

$\dashrightarrow{ \sf{4 {x}^{2} + 4 {x}^{2} - 2x + 4x + 28 - 55}}$

$\dashrightarrow{ \sf{8 {x}^{2} + 2x + 28 - 55}}$

The negative and positive integers are always subtracted but possess the sign of the bigger integer.

$\dashrightarrow{ \sf{8 {x}^{2} + 2x - 27}}$

Hope I helped!

Best regards! :D