Answer:
B
Step-by-step explanation:
Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
Answer:
4√10xy/32y is the answer. (I think)
Multiply the equation:

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

Multiplying this by 3 (or whatever number, for all it matters) gives

Now, a product is zero if and only if at least one of the factor is zero. So, either
or 
Since the first is clearly impossible, the second one must be true, which is the original equation.
Hello there,
To write an improper fraction you will have to divide whole number by denominator than add the numerator...
7 * 1 = 7
7 + 4 = 11
The denominator stays the same...
11/7
Answer: 11/7
Hope I helped!!
-Char