Answer:
The carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Step-by-step explanation:
Given:
Amount a carpenter can spend at most = $250
The inequality to represent the amount he can spend on each type of board is given as:
where 
represents '2 by 8 boards' and 
represents '4 by 4 boards'.
To determine whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Solution :
In order to check whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards' , we need to plugin the 
and 
in the given inequality and see if it satisfies the condition or not or in other words (12,14) must be a solution for the inequality.
Plugging in and in the given inequality
The above statement can never be true and hence the carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B2%7D%7B%20h%7D%2C%5Cstackrel%7B-1%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D2%5C%5C%20k%3D-1%20%5Cend%7Bcases%7D%5Cimplies%20y%3Da%28x-2%29%5E2-1%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20y%3D0%5C%5C%20x%3D5%20%5Cend%7Bcases%7D%5Cimplies%200%3Da%285-2%29%5E2-1%5Cimplies%201%3D9a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B1%7D%7B9%7D%3Da%5Cqquad%20therefore%5Cqquad%20%5Cboxed%7By%3D%5Ccfrac%7B1%7D%7B9%7D%28x-2%29%5E2-1%7D)
now, let's expand the squared term to get the standard form of the quadratic.
Answer:
468 ways
Step-by-step explanation:
Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts
To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.
Solution:
A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.
Number of appetizers = 5
Number of main courses = 4
Number of desserts = 8
Number of ways of choosing k terms from n terms = 
Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = 
So, this can be done in 468 ways.
Same case as Pablo's, more or less.
a = price for the desktop
b = price for the laptop
we know the laptop is 150 bucks more than the desktop,
b = a + 150.
how much is 7% of a? (7/100) * a, 0.07a.
how much is 9.5% of b? (9.5/100) * b, 0.095b.
total interests for the financing add up to 303,
0.07a + 0.095b = 303.
how much was it for the laptop? well b = a + 150.
Answer:
(√2) / 3
Step-by-step explanation:
√(2/9) =√(2/3^2) =(√2)/3
