Given: A= 14 ft² and l= 2w-3
formula for area of a rectangle is A=lw
substitute for what you know and simplify:
14=(2w-3)w -> w= either -2 or 7/2 but because a width value can not be negative you can eliminate the -2 value. w=7/2
subsitute width into equation for length and solve
l=2w-3= 2(7/2)-3= 4
width: 3.5 ft
length: 4 ft
Answer:
4:3
Step-by-step explanation:
He has 4 Soccer Medals, 3 Swimming Medals
So it would be 4:3
Where's the "triangle with alt. BD?" This problem can be solved without the diagram, but the solution would be easier with it.
BD is the altitude. Find the length of BD by finding the dist. between (-1,4) and (2,4); it is 2-(-1), or 3. |BD| = 3.
I've graphed the triangle myself and have found that the "base" of the triangle is the vertical line thru (2,1) and (2,6); its length is 6-1, or 5.
Thus, the area of this triangle is A = (b)(h) / 2, or A = (5)(3) / 2 = 10/3 square inches.
Answer:
The line is 
.
Step-by-step explanation:
Given:
Point and slope (0,0) and 2/3.
Now, to determine the line.
Here the point is:
And the slope is:
Now, putting the formula and substituting the value from above to determine the line:
Therefore, the line is .
Answer:
a) PR = 17 cm, b) QR = 6 cm
Step-by-step explanation:
∠Q=90, so PQ and QR are legs, and PR is hypotenuse.
Pythagorean theorem PQ² + QR² = PR²
a) PQ² + QR² = PR²
8² + 15² = PR²
PR² = 289
PR = 17 cm
b) PQ² + QR² = PR²
8² + QR² = 10²
64 + QR² = 100
QR² = 36
QR = 6 cm
