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mina [271]
2 years ago
14

Part A: The decimal form of the rational number 3/40 is

Mathematics
1 answer:
Gnom [1K]2 years ago
8 0

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | }  \\ \bf{Part  \: A} & \bf \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}} \\  \\   \hline \\  \bf{Part  \: B}& \:  \bf \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  } \\  \\ \hline \\ { \bf Part  \:C \: }&  \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. \:  \:  \:  \:  \:  \:  \:  \:  }}    \\  \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

\bf \underline{Answer-} \\

{ \bf{Part  \: A \:  | \:  \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}}}}

{ \bf{Part  \: B \:  | \:  \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3   }}}

\bf \underline{Step \:by \:step\: Explanation-} \\

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[4]{(9)^{ - 2} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[ \cancel4]{(9)^{ \cancel{ - 2}} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt{9^{  - 1} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{  {3}^{ - 1  } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{   \dfrac{1}{3}  }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies3}

{ \bf Part  \:C \: } | \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. }}

{~~~\sf ~~:~~\implies (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7})}

{~~~~\sf ~:~~\implies 5+ \cancel{3 \sqrt{7}} + 12 \cancel{ - 3 \sqrt{7}}}

{~\sf ~~~~:~~\implies 17}

\underline{\rule{200pt}{2.5pt}}

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Then draw 4 rectangles that are vertical or horizontal. Make sure the rectangle is longer than it is wide, or vice versa. The longer side is t units long (t is just a placeholder for a number). The shorter side is 1 unit long

The longer thin rectangles have an area of 1*t = t square units. Four of them represent t+t+t+t = 4*t = 4t
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This is one possible way to draw it out. See the attached drawing. 

4 0
3 years ago
The volume in cubic centimeters of a sphere whose diameter is 6 centimes is ?
aivan3 [116]

Answer:

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Step-by-step explanation:

given \\ diameter \: of \: sphere = 6 \: cm \\ radius \: of \: sphere \:  =  \frac{diameter}{2}  \\ radius \:  =  \frac{6}{2}  \\ radius \: (r) =  \: 3 \: cm \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {r}^{3}  \\ here \: r \:  = 3 \: cm \\ on \: substituting \: r \:  = 3 \:  \: in \: formula \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {3}^{3}  \\  \:  \:  =  \frac{4}{3} \pi \: 27 \\   \:   = \: 4 \pi \times 9 \\  \:  \:  = 36\pi \\  \:  \:  = 113.097 \:  {cm}^{3}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
ILL MARK BRAINLEST When Josiah opens and lays a cereal box out flat, he sees that the top and the bottom of the box both measure
Elan Coil [88]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
6x-4bracket(2x-5)&gt;8 or 5x+9&lt;2x-21
Yuri [45]

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<h3>Linear Inequalities </h3>

From the question, we are to solve the given inequalities

The given inequalities are

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First solve,

6x - 4(2x - 5) > 8

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Divide both sides by -2 and flip the sign,

That is,

-2x/-2 > -12/-2

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For,

5x + 9 < 2x - 21

Subtract 2x from both sides

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Divide both sides by 3

3x/3 < -30/3

x < -10

Hence, the solutions to the given inequalities are x < 6 OR x < -10

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1

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1 year ago
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Answer:

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The percentage increase between the amount of offenses in 2000 and the amount of offenses in 2019 is approximately 262%.

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3 years ago
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