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3 years ago

5. One teacher and 23

Mathematics

1 answer:

Lena [83]3 years ago

5 0

Answer: 396

Step-by-step explanation:

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A basketball player Made 63 out of 75 free throws what percent is this

Kazeer [188]

Answer: 84%

Step-by-step explanation:

1. You divide: 63/75

2. Your answer is 0.84

3. You convert it into a percent by moving the decimal two times to the right

4. You get 84%

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3 years ago

Please help! Graph the line for y+1=−3/5(x−4) on the coordinate plane. I just need help with the coordinates.

otez555 [7]

Answer:

SLOPE: - 3/5

Y-INTERCEPT: 7/5

Step-by-step explanation: Check picture :)

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3 years ago

What is the fully factored form of 32a3 + 12a2? 4a2(8a + 3) 4a(8a2 + 3a) 12a2(3a + 1) 12a(3a2 + a)

ad-work [718]

Answer:

4a^2 (8a+3)

Step-by-step explanation: it’s right

5 0

3 years ago

Read 2 more answers

Julia is going to the store to buy candies. Small candies cost $4 and extra-large candies cost $12.She needs to purchase at leas

BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

2 years ago

Find a quadratic equation with roots -1, 4i and -1 - 4i

vazorg [7]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
\textit{also recall that }i^2=-1\\\\
-------------------------------\\\\
\begin{cases}
x=-1+4i\implies &x+1-4i=0\\
x=-1-4i\implies &x+1+4i=0
\end{cases}
\\\\\\
(x+1-4i)(x+1+4i)=\stackrel{y}{0}
\\\\\\\
[(x+1)~~-~~(4i)][(x+1)~~+~~(4i)]=y
\\\\\\\
[(x+1)^2~~-~~(4i)^2]=0\implies (x^2+2x+1)~-~(4^2i^2)=y
\\\\\\
(x^2+2x+1)~-~(16\cdot -1)=y\implies (x^2+2x+1)~-~(-16)=y
\\\\\\
x^2+2x+1~~+16=y\implies x^2+2x+17=y$

3 0

3 years ago