5. One teacher and 23

Calculate 6/√2 and express it in form of a√b

LekaFEV [45]

Answer:

$3 \sqrt{2}$

Step-by-step explanation:

$\frac{6}{ \sqrt{2} } = \frac{6}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{6 \sqrt{2} }{2} = 3 \sqrt{2}$

We can't have a fraction that has a number under square root as it's denominator. So we will have to rationalize it, which means we will multiply the numerator and also the denominator by the number that is under the square root.

Hope this helps ;) ❤❤❤

4 0

3 years ago

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A container shape as a rectangular prism can hold 840 wooden cube blocks with edge lengths of 1/2 feet. What is the volume of th

zhuklara [117]

The first thing we should know is that the volume of a cube by definition is:
V = L ^ 3
Where:
L: side.
We have then that the volume of a cube is:
V = (1/2) ^ 3
V = 1/8
Then, the prism volume is:
Vtotal = 840 * V
Vtotal = 840 * (1/8)
Vtotal 105 feet ^ 3
Answer:
the volume of the prism is:
Vtotal 105 feet ^ 3

3 0

3 years ago

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8 The length of Adriana's chicken coop is 3x + 12 feet. The length of her garden is

algol13

Answer:

Rounded down to the nearest foot, the length of the garden is nine feet.

Step-by-step explanation:

We're told that the length of the chicken coop, 3x + 12 feet, is equal to the length of the garden, 6x - 16 feet. Let's put them together then and solve for x:

3x + 12 = 6x - 16

First, we'll subtract 6x from both sides

3x - 6x + 12 = 6x - 6x - 16

-3x + 12 = -16

Now we subtract 12 from both sides:

-3x + 12 - 12 = -16 - 12

-3x = -28

Finally divide both sides by -3

-3x / -3 = -28 / -3

x = 28/3

x = 9 and 1/3

As the question asks for the number of feet only (not inches), the answer is nine feet.

A third of a foot though is four inches, so the more exact answer is nine feet and four inches, or 9'4"

4 0

3 years ago

Troy made a scale drawing of the Statue of Liberty which has an actual height of 305 feet. He decides to use a scale in which 1

sergiy2304 [10]

The height of statue is 12.2 inches in Troy's drawing.

Step-by-step explanation:

Given,

Actual height of statue = 305 feet

Scale used by Troy;

25 feet = 1 inch

1 feet = $\frac{1}{25}\ inches$

305 feet = $\frac{1}{25}*305 \ inches$

305 feet = $\frac{305}{25}\ inches\\$

305 feet = 12.2 inches

The height of statue is 12.2 inches in Troy's drawing.

Keywords: unit rate, division

Learn more about unit rate at:

#LearnwithBrainly

3 0

4 years ago

Use the method of variation of parameters to find a particular solution of the given differential equation. Then check your answ

olga_2 [115]

Answer:

Therefore the complete primitive is

$y=c_1 e^{2y}+c_2e^{3t}+e^{t}$

Therefore the general solution is

$y=c_1e^{2t}+c_2e^{3t}+e^t$

Step-by-step explanation:

Given Differential equation is

$y''-5y'+6y=2e^t$

<h3>Method of variation of parameters:</h3>

Let $y=e^{mt}$ be a trial solution.

$y'= me^{mt}$

and $y''= m^2e^{mt}$

Then the auxiliary equation is

$m^2e^{mt}-5me^{mt}+6e^{mt}=0$

$\Rightarrow m^2-5m+6=0$

$\Rightarrow m^2 -3m -2m +6=0$

$\Rightarrow m(m -3) -2(m -3)=0$

$\Rightarrow (m-3)(m-2)=0$

$\Rightarrow m=2,3$

∴The complementary function is $C_1e^{2t}+C_2e^{3t}$

To find P.I

First we show that $e^{2t}$ and $e^{3t}$ are linearly independent solution.

Let $y_1=e^{2t}$ and $y_2= e^{3t}$

The Wronskian of $y_1$ and $y_2$ is $\left|\begin{array}{cc}y_1&y_2\\y'_1&y'_2\end{array}\right|$

$=\left|\begin{array}{cc}e^{2t}&e^{3t}\\2e^{2t}&3e^{3t}\end{array}\right|$

$=e^{2t}.3e^{3t}-e^{2t}.2e^{3t}$

$=e^{5t}$ ≠ 0

∴ $y_1$ and $y_2$ are linearly independent.

Let the particular solution is

$y_p=v_1(t)e^{2t}+v_2(t)e^{3t}$

Then,

$Dy_p= 2v_1(t)e^{2t}+v'_1(t)e^{2t}+3v_2(t)e^{3t}+v'_2(t)e^{3t}$

Choose $v_1(t)$ and $v_2(t)$ such that

$v'_1(t)e^{2t}+v'_2(t)e^{3t}=0$ .......(1)

So that

$Dy_p= 2v_1(t)e^{2t}+3v_2(t)e^{3t}$

$D^2y_p= 4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}$

Now

$4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}-5[2v_1(t)e^{2t}+3v_2(t)e^{3t}] +6[v_1e^{2t}+v_2e^{3t}]=2e^t$

$\Rightarrow 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}=2e^t$ .......(2)

Solving (1) and (2) we get

$v'_2=2 e^{-2t}$ and $v'_1(t)=-2e^{-t}$

Hence

$v_1(t)=\int (-2e^{-t}) dt=2e^{-t}$

and $v_2=\int 2e^{-2t}dt =-e^{-2t}$

Therefore $y_p=(2e^{-t}) e^{2t}-e^{-2t}.e^{3t}$

$=2e^t-e^t$

$=e^t$

Therefore the complete primitive is

$y=c_1 e^{2y}+c_2e^{3t}+ e^{t}$

<h3>Undermined coefficients:</h3>

∴The complementary function is $C_1e^{2t}+C_2e^{3t}$

The particular solution is $y_p=Ae^t$

Then,

$Dy_p= Ae^t$ and $D^2y_p=Ae^t$

$\therefore Ae^t-5Ae^t+6Ae^t=2e^t$

$\Rightarrow 2Ae^t=2e^t$

$\Rightarrow A=1$

$\therefore y_p=e^t$

Therefore the general solution is

$y=c_1e^{2t}+c_2e^{3t}+e^t$

4 0

3 years ago