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tresset_1 [31]
3 years ago
8

Pomógłbymi ktoś z takim zadaniem? C++

Computers and Technology
1 answer:
Elenna [48]3 years ago
8 0

#include <iostream>

using namespace std;

int main(int argc, char** argv) {

 

int n;

cout<<"Podaj n: ";

cin>>n;

 

int **tab=new int *[n];

 

for(int i=0;i<n;i++){

 tab[i]=new int [n];

}

 

for (int l=0;l<n;l++){

 for(int j=0;j<n;j++){

  if(j==l || n-l-1==j) tab[l][j]=0;

  else tab[l][j]=1;

 }

}

 

 for (int i=0;i<n;i++){

 for(int j=0;j<n;j++){

 cout<<tab[i][j];

 }

 cout<<"\n";

}

 

for(int i=0;i<n;i++){

  delete [] tab[i];

}

delete [] tab;

return 0;

}

Siema Marcin tak wgl.

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Answer:

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2. support the development of general reasoning, problem-solving and communication skills.

3. Through avoiding in repetious tasks and simplifying such works.

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Public class Bird
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Answer:

Answer below.

Explanation:

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{

super(beak);

talonStrength = talon;

}

Please mark brainliest if this is the answer you were looking for

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What is the purpose of flight simulator programs, and what are some of the benefits of using them?
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Answer:

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Explanation:

hope this helps <3

6 0
2 years ago
Read 2 more answers
Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
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Which of the following statements about renting and owning
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