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3 years ago

Pomógłbymi ktoś z takim zadaniem? C++

Computers and Technology

1 answer:

Elenna [48]3 years ago

8 0

#include <iostream>

using namespace std;

int main(int argc, char** argv) {

int n;

cout<<"Podaj n: ";

cin>>n;

int **tab=new int *[n];

for(int i=0;i<n;i++){

tab[i]=new int [n];

}

for (int l=0;l<n;l++){

for(int j=0;j<n;j++){

if(j==l || n-l-1==j) tab[l][j]=0;

else tab[l][j]=1;

}

for (int i=0;i<n;i++){

for(int j=0;j<n;j++){

cout<<tab[i][j];

}

cout<<"\n";

}

for(int i=0;i<n;i++){

delete [] tab[i];

}

delete [] tab;

return 0;

}

Siema Marcin tak wgl.

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3 years ago

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3 years ago

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Elis [28]

Answer:

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Let a,b be two numbers.

c=a+b;

print(c);

But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:

Let a be the variable where the input numbers are stored.

while(f==1)

{

printf(“Enter number”);

scanf(“Take number into the variable a”);

sum=sum+a;

printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);

scanf(“Take the input into the variable f”);

}

print(Sum)

Explanation:

hi there answer is given mar me as brainliest

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3 years ago

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2 years ago

1.Write a Java program to solve the following problem using modularity. Write a method that rotates a one-dimensional array with

Westkost [7]

Answer:

Explanation:

The following code is written in Java and it asks the user for the size of the array. Then it randomly populates the array and prints it. Next, it rotates all the elements to the right by 1 and prints the new rotated array.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

import java.util.Scanner;

class Brainly {

public static void main(String[] args) {

Random r = new Random();

Scanner in = new Scanner(System.in);

System.out.println("Enter Size of the Array: ");

int arraySize = in.nextInt();

ArrayList<Integer> myList = new ArrayList<>();

for (int x = 0; x < arraySize; x++) {

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}

System.out.println("List Before Rotation : " + Arrays.toString(myList.toArray()));

for (int i = 0; i < 1; i++) {

int temp = myList.get(myList.size()-1);

for (int j = myList.size()-1; j > 0; j--) {

myList.set(j, myList.get(j - 1));

}

myList.set(0, temp);

}

System.out.println("List After Rotation : " + Arrays.toString(myList.toArray()));

}

6 0

2 years ago