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Sauron [17]
3 years ago
6

There is no need to schedule video calls ahead of time; they can be used the same way as

Computers and Technology
1 answer:
UNO [17]3 years ago
6 0

Answer:

The answer to this question is "True".

Explanation:

The term video calling is part of communication. In this type of communication will be used in every place like house, office for video conferencing, etc. It was developed in 1968 by AT&T's Bell Labs. It works on internet.This type of calling we can face to face communicate means, we watch the person. In the video calling, there is no need for a schedule it is used as a phone call.  

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In 2-5 paragraphs, describe the points that Kendra needs to consider when choosing a telecommunications technology to meet her n
never [62]

Answer:

For marketing requirements, various communication mediums like digital communication medium, as well as non digital traditional communication medium can be used. Some like Blogs, Article directories, forums etc. can be used.

However, the AI, ML, DL and the traditional statistical analysis from Data Science can also be used. You need to install on your blog the chat-bots, And through the Chat-bots we can make a data set, that is in fact automatically generated, and contains email, phone numbers, addresses etc, and this data base can be used to run the Amazon Sage-makers. and a lot of meaningful information can be achieved through the prepared data-set through the Sage-maker.

Thus, you can find out quite easily what is good.

Sage maker, Chat bots and Blog technology is quite cost effective as well.

Explanation:

The above details covers all the requirements.

7 0
3 years ago
How do you install an operating system?<br><br> Answer with full sentences
denis23 [38]

Answer:

On Windows. Insert the installation disk or flash drive. Restart your computer. Wait for the computer's first startup screen to appear. Press and hold Del or F2 to enter the BIOS page. Locate the "Boot Order" section. Select the location from which you want to start your computer.

Explanation:

6 0
3 years ago
Adios brainly, wont be posting that much take my points away i d c
mrs_skeptik [129]
Omg I would die to have your points because when I get on people call me a noob because I just got the app like 3 days ago and every time I answer a question some says noob like dang I just started
5 0
3 years ago
Read 2 more answers
What are the consequences of having unprotected Linux operating systems installed on embedded systems?
Gennadij [26K]

Answer:

highly venerable to external attacks

Explanation:

Embedded systems are the type of computer systems that are specially designed having hardware and software components plus programmable  capabilities embedded into the hardware itself.

These computer systems are motorized by dedicated computer hardware chips made by companies such as Broadcom, Qualcomm, and Marvell. These chips are cheap which also means that they’re highly vulnerable, and the profit margins slim. They normally put a version of the Linux operating system onto the chips, lumping it up with some other bunch of open-source and proprietary components and drivers. With little or no technical engineering work before shipping, and there's little enticement to update their "board support package" until there’s probably a very good reason for it.

6 0
3 years ago
Develop a plan to design and finally implement a set of functions using C++ that would implement the IEEE standard. Phase 1 will
AnnZ [28]

Answer:

See explaination code

Explanation:

#include<iostream>

#include<math.h>

using namespace std;

typedef union {

float number;

struct

{

// Order is important.

// Here the members of the union data structure

// use the same memory (32 bits).

// The ordering is taken

// from the LSB to the MSB.

unsigned int mantissa : 23;

unsigned int exponent : 8;

unsigned int sign : 1;

} Raw;

} MyFloat;

void printBinary(int n, int i)

{

// Prints the binary representation

// of a number n up to i-bits.

int k;

for (k = i - 1; k >= 0; k--) {

if ((n >> k) & 1)

cout << "1";

else

cout << "0";

}

}

void decToHex(int n){

// char array to store hexadecimal number

char hexaDeciNum[100];

// counter for hexadecimal number array

int i = 0;

while(n!=0)

{

// temporary variable to store remainder

int temp = 0;

// storing remainder in temp variable.

temp = n % 16;

// check if temp < 10

if(temp < 10)

{

hexaDeciNum[i] = temp + 48;

i++;

}

else

{

hexaDeciNum[i] = temp + 55;

i++;

}

n = n/16;

}

// printing hexadecimal number array in reverse order

for(int j=i-1; j>=0; j--)

cout << hexaDeciNum[j];

}

void floatBinary(float f){

long double binaryTotal, binaryFrac = 0.0, frac, fracFractor = 0.1;

long int integer, binaryInt = 0;

long int p = 0, rem, temp;

//separate the integer part from the input floating number

integer = (int)f;

//separate the fractional part from the input floating number

frac = f - integer;

//loop to convert integer part to binary

while (integer != 0) {

rem = integer % 2;

binaryInt = binaryInt + rem *pow(10, p);

integer = integer / 2;

p++;

}

//loop to convert fractional part to binary

while (frac != 0) {

frac = frac * 2;

temp = frac;

binaryFrac = binaryFrac + fracFractor * temp;

if (temp == 1)

frac = frac - temp;

fracFractor = fracFractor / 10;

}

cout << binaryInt + binaryFrac;

}

int findDecimal(float number){

int nfloor = number;

float nfloat = number - nfloor;

int nfloatfloor;

do {

nfloat *= 10;

nfloatfloor = nfloat;

} while (nfloat > nfloatfloor);

return nfloatfloor;

}

void first(float number){

if(number < 0)

cout << "SIGN BIT IS (1) SINCE NUMBER IS NEGATIVE" << endl;

else

cout << "SIGN BIT IS (0) SINCE NUMBER IS POSITIVE" << endl;

}

void second(float number){

cout << "INTEGER PART IN BASE-10:" << int(number) << " AND IN BINARY:";

printBinary(int(number),16);

cout << endl;

}

void third(float number){

cout << "DECIMAL PART IN BASE-10:" << findDecimal(number) << " AND IN BINARY:";

printBinary(findDecimal(number),16);

cout << endl;

}

void fourth(float number){

cout << "ENTERED NUMBER IN BASE-10:" << number << " AND IN BINARY:";

floatBinary(number);

cout << endl;

}

void fifth(MyFloat myfloat){

cout << "MANTISA IN BINARY:";

printBinary(myfloat.Raw.mantissa,32);

}

void sixth(MyFloat myfloat){

cout << "EXPONENT IN BASE-10:" << myfloat.Raw.exponent << " AND IN BINARY:";

printBinary(myfloat.Raw.exponent,8);

cout << endl;

}

void seventh(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

printBinary(myfloat.Raw.exponent,8);

cout << " | ";

printBinary(myfloat.Raw.mantissa,32);

cout << endl;

}

void eigth(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

decToHex(myfloat.Raw.exponent);

cout << " | ";

decToHex(myfloat.Raw.mantissa);

cout << endl;

}

int main(){

float number;

cout << "PLEASE ENTER A NUMBER TO DISPLAY THE IEEE 754 FLOATING POINT OPTIONS" << endl;

cin >> number;

MyFloat myfloat;

myfloat.number = number;

cout << "PLEASE CHOOSE ONE OF THE FOLLOWING OPERATIONS" << endl;

cout << " 1. DISPLAY THE SIGN BIT VALUE" << endl;

cout << " 2. DISPLAY THE INTEER PART IN BOTH BASE-10 AND CINARY FORMATS" << endl;

cout << " 3. DISPLAY THE DECIMAL PART IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 4. DISPLAY THE NUMBER ENTERED IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 5. DISPLAY THE MANTISA IN BINARY FORMATS" << endl;

cout << " 6. DISPLAY THE EXPONENT IN BORH BASEE-10 AND BINARY FORMATS" << endl;

cout << " 7. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

cout << " 8. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

int choice;

cin >> choice;

switch(choice){

case 1:first(number);

break;

case 2:second(number);

break;

case 3:third(number);

break;

case 4:fourth(number);

break;

case 5:fifth(myfloat);

break;

case 6:sixth(myfloat);

break;

case 7:seventh(myfloat);

break;

case 8:eigth(myfloat);

break;

default:cout << "ENTER VALID CHOICE" << endl;

}

}

Refer to attachment please for onscreen look.

6 0
3 years ago
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