Answer:
Unicode
Explanation:
This is a fairly large code and Is well known throughout my family since we study ancient codex and modern codes to solve crimes and find relics of the past, although our research has proven good and unicode is one that is being studied currently now, I have found it as long and very time consuming. Although ASCII is a computer code that consists of graphs and numbers it actually shortens the text. and hexadecimal has been proven to be less reliable and binary is a short code with little symbols
Answer:
The answer to this question is Yes it is possible
Explanation:
It can be done In the case where a special server is required in each network that would forward the request to the remote ARP(Address Resolution Protocol) server and will receive the response from the server and send it to the requesting host.So we conclude that we can do that hence the answer is Yes.
Answer:
-19/32
Explanation:
(If I assume d to be x)
4x+3/8=-2
or,4x=-2-3/8=-19/8
or,x=(-19/8)*(1/4)=-19/32
Answer:
A = 5 + 1.75r
Explanation:
Amount you have = $5
Earning per roll of wrapping paper = $1.75
Let
r = number of rolls of wrapping paper
A = Total amount earned
A = 5 + 1.75r
Equation that represents the total amount A (in dollars) you have after selling r rolls of wrapping paper is
A = 5 + 1.75r
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
