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Dvinal [7]
4 years ago
9

3. How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot? Why do you think this h

appens?
Physics
1 answer:
m_a_m_a [10]4 years ago
3 0

Answer:

the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.

Explanation:

A conductor that does not obey Ohm's law is described as non - ohmic. An example is a filament lamp. It glows as the current passes through it.

How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot ?

The resistance of the light bulbs increase gradually as its temperature is increased.

So, the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.

Because the resistance of an impure metal wire is greater than the resistance of a pure metal wire of the same dimension.

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A light bulb has a voltage of 36 and a current of 8 A. Calculate the resistance of the light bulb
timurjin [86]
R = U : I. U is in Voltage and I is in Ampère. That gives you R = 36 : 8 = 4,5 Ohm
4 0
3 years ago
A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s
topjm [15]

Answer:

\Delta U = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

Explanation:

The electrostatic potential energy is given by the following formula

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Now, we will apply this formula to both cases:

U_1 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_1^2}\\U_2 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_2^2}

So, the change in the potential energy is

\Delta U = U_2 - U_1 = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

7 0
3 years ago
Which of the following would most likely be considered nonpoint source pollution
fredd [130]
The best answer is b) increased turbidity from erosion.

Nonpoint source pollution generally happens as a result of many systems interacting, and is not directly attributed to one event or pollutant. Generally, natural environmental systems participate in pollution of this kind, regardless of whether or not human activity was a factor. Examples include water runoff, or erosion. 

The other pollutants listed have a direct cause and direct effect, the animal waste goes directly from the animals to the ground they live on, the car shop directly sumps the oil on the ground, and the oil tank leaks directly into the earth. Erosion causing turbidity is a less direct form of pollution, and is due to the synthesis of several natural phenomena<span />
8 0
4 years ago
If you ride quickly down a hill on a bicycle your eardrums are pushed in before they pop back. Why is this?
Mice21 [21]

Answer:

<em>The difference in pressure between the external air pressure, and the internal air pressure of the middle ear.</em>

Explanation:

First of all, we should note that pressure decreases with height and increases with depth. The air within the middle ear (between the ear drum and the Eustachian tube) adjusts itself to respond to the atmospheric pressure, or when we yawn.  At a high altitude like on the hill, the air pressure in the middle ear, is fairly low (this is to balance the low air pressure at this height). While riding down the hill quickly, there is little time for the air pressure in the ear to readjust itself to the increasing external air pressure, causing the external air to push into the ear drum. Along the way, the air within the middle ear is adjusted by the opening of the Eustachian tube, allowing more air into the space in the middle ear to balance the external air pressure. This readjustment causes the ear to pop.

7 0
3 years ago
Two Jupiter-size planets are released from rest 1.40×10^11 m apart.. What are their speeds as they crash together?
Sonbull [250]
M₁ = mass of planet #1 
M₂ = mass of planet #2 
M = total mass 
R₁ = radius of planet #1 
R₂ = radius of planet #2 
d₁ = initial distance between planet centers 
d₂ = final distance between planet centers 
a = semimajor axis of plunge orbit 
v₁ = relative speed of approach at distance d₁ 
v₂ = relative speed of approach at distance d₂ 

M₁ = M₂ = 1.8986e27 kilograms 
M = M₁ + M₂ = 3.7972e27 kg 
G = 6.6742e-11 m³ kg⁻¹ sec⁻² 
GM = 2.5343e17 m³ sec⁻² 
d₁ = 1.4e11 meters 
a = d₁/2 = 7e10 meters 
R₁ = R₂ = 7.1492e7 meters 
d₂ = R₁ + R₂ = 1.42984e8 meters 
v₁ = 0 
v₂ = √[GM(2/d₂−1/a)] 
<span>
v₂ = 59508.4 m/s </span>
<span>
The time to fall is 1337.7 days

.</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly.
7 0
4 years ago
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