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viktelen [127]
3 years ago
9

A piece of glass weights 25 g in air, 16.77g in water at 4C and 16.89g in water at 60C. Find the mean coefficient of cubical exp

ansion of water between 4C anf 60C, taking the coefficient of linear expansion of glass as 8*10^6​
Physics
1 answer:
Oksanka [162]3 years ago
7 0

sorry i think so i dont exactly know i am sorry

Explanation:

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Can anyone pls help me with this I’ll appreciate it. I’m trying to study for a test but I don’t know the answer to this.
forsale [732]

Answer:

okay so what you will do is where is says red giant you will write all about what it talks about red giants only, and the box plantary nebulas you will write about what is says about only planetary nebulas. x- hope this helps :)

Explanation:

7 0
2 years ago
Suppose your hair grows at the rate 1/31 in. per day. find the rate at which it grows in nanometers per second. because the dist
kati45 [8]
Hair grows at rate of 9.20nm/s.
7 0
3 years ago
A 60 W light bulb is powered by a connection to a wall outlet with 120 V across the plug terminals. a) What is the current passi
Oxana [17]

Answer:

The current through the resistor is 0.5 A

Explanation:

Given;

power of the light bulb = 60 W

voltage in the wall outlet across the plug terminals = 120 V

power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.

power = voltage x current

Current = \frac{power}{voltage} = \frac{60}{120} = 0.5 A

Therefore, for a  60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A

7 0
3 years ago
Read 2 more answers
1. Define friction. Name and describe two kinds of friction.
jeka57 [31]

Answer:

Friction is a force that holds back the movement of a sliding object.

Explanation:

The two types of friction: Static friction and Kinetic friction.  Static friction operates between two surfaces that aren't moving relative to each other, while kinetic friction acts between objects in motion.

6 0
3 years ago
Consider the same roller coaster. It starts at a height of 40.0 m but once released, it can only reach a height of 25.0 m above
poizon [28]

Answer:

The magnitude of the frictional force between the car and the track is 367.763 N.

Explanation:

The roller coster has an initial gravitational potential energy, which is partially dissipated by friction and final gravitational potential energy is less. According to the Principle of Energy Conservation and Work-Energy Theorem, the motion of roller coster is represented by the following expression:

U_{g,1} = U_{g,2} + W_{dis}

Where:

U_{g,1}, U_{g,2} - Initial and final gravitational potential energy, measured in joules.

W_{dis} - Dissipated work due to friction, measured in joules.

Gravitational potential energy is described by the following formula:

U = m \cdot g \cdot y

Where:

m - Mass, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

y - Height with respect to reference point, measured in meters.

In addition, dissipated work due to friction is:

W_{dis} = f \cdot \Delta s

Where:

f - Friction force, measured in newtons.

\Delta s - Travelled distance, measured in meters.

Now, the energy equation is expanded and frictional force is cleared:

m \cdot g \cdot (y_{1} - y_{2}) = f\cdot \Delta s

f = \frac{m \cdot g \cdot (y_{1}-y_{2})}{\Delta s}

If m = 1000\,kg, g = 9.807\,\frac{m}{s^{2}}, y_{1} = 40\,m, y_{2} = 25\,m and \Delta s = 400\,m, then:

f = \frac{(1000\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (40\,m-25\,m)}{400\,m}

f = 367.763\,N

The magnitude of the frictional force between the car and the track is 367.763 N.

7 0
3 years ago
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