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prohojiy [21]
3 years ago
9

A static electric charge can be released as __________. *

Physics
2 answers:
poizon [28]3 years ago
8 0
A, a spark because if you touch something after rubbing your hand on carpet or something you get a spark
Inessa05 [86]3 years ago
8 0

Answer:

C. A continuous current.

Explanation:

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In a physics lab, a 0.500-kg cart (Cart A) moving with a speed of 129 cm/s encounters a magnetic collision with a 1.50-kg cart (
omeli [17]

Answer:

58 cm/s

Explanation:

0.5×129=0.5×(-45)+1.5×V

V=58

7 0
2 years ago
A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para
Firlakuza [10]

Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e   Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

     = 20 Nm

The work done by the father is 20 Joules(Nm).

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3 years ago
If a small number of tree frogs migrate to a mat of vegetation that is already home to an established population of tree frogs a
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D

Explanation:

Gene flow is the transfer of genetic variation from one population to another

5 0
3 years ago
What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

3 0
3 years ago
Describe the relationship between kinetic energy and speed and give an example of how changing and object speed would affect its
Andreas93 [3]

Answer:

I'm not sure

Explanation:

I have had that question to Uchida c r go crew in to go be

6 0
2 years ago
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