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saul85 [17]
3 years ago
12

Students measure the length of their feet in inches. The data is shown in the frequency table below. If the data were displayed

in a dot plot, which of the measures would not be 11? (Check all that apply.)
Foot Length Tally Frequency

9 || 2

10 ||| 3

11 ||||| 5

12 | 1


range

mode

median

mean
Mathematics
2 answers:
IrinaK [193]3 years ago
4 0

this is not an answer but are you doing 6th-grade monarch????????? meeeee tooooo if so

skelet666 [1.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

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Probability, pleaseeeeeeeee help!
balu736 [363]

Answer:

24

Step-by-step explanation:

You don't really need to do a permutation here. We know that there are 4 options for digits and three places so therefore we have 4 choices for the first digit, 3 for the second and 2 for the last so the answer is 4 * 3 * 2 = 24.

3 0
3 years ago
1. Given (x) =1/2(x + 4)(x – 11), use your graphing calculator to graph this function and
marin [14]
Here are my answers!
the only one i’m not completely sure of is #4 but i’m assuming it’s where the function is above and below the x-axis

6 0
3 years ago
Let H and K be subgroups of a group G, and let g be an element of G. The set <img src="https://tex.z-dn.net/?f=%5Cmath%20HgK%20%
34kurt

Answer:

Yes, double cosets partition G.

Step-by-step explanation:

We are going to define a <em>relation</em> over the elements of G.

Let x,y\in G. We say that x\sim y if, and only if, y\in HxK, or, equivalently, if y=hxk, for some h\in H, k\in K.

This defines an <em>equivalence relation over </em><em>G</em>, that is, this relation is <em>reflexive, symmetric and transitive:</em>

  • Reflexivity: (x\sim x for all x\in G.) Note that we can write x=exe, where e is the <em>identity element</em>, so e\in H,K and then x\in HxK. Therefore, x\sim x.
  • Symmetry: (If x\sim y then y\sim x.) If x\sim y then y=hxk for some h\in H and k\in K. Multiplying by the inverses of h and k we get that x=h^{-1}yk^{-1} and is known that h^{-1}\in H and k^{-1}\in K. This means that x\in HyK or, equivalently, y\sim x.
  • Transitivity: (If x\sim y and y\sim z, then x\sim z.) If x\sim y and y\sim z, then there exists h_1,h_2\in H and k_1,k_2\in K such that y=h_1xk_1 and z=h_2yk_2. Then, \\ z=h_2yk_2=h_2(h_1xk_1)k_2=(h_2h_1)x(k_1k_2)=h_3xk_3 where h_3=h_2h_1\in H and k_3=k_1k_2\in K. Consequently, z\sim x.

Now that we prove that the relation "\sim" is an equivalence over G, we use the fact that the <em>different equivalence classes partition </em><em>G.</em><em> </em>Since the equivalence classes are defined by [x]=\{y\in G\colon x\sim y\} =\{y\in G \colon y=hgk\ \text{for some } h\in H, k\in K \}=HxK, then we're done.

5 0
3 years ago
Yoko bought 22 pounds of flour for $9. How many dollars did she pay per pound of flour?
kirill115 [55]

Answer:

$0.41

Step-by-step explanation:

"per pound" tells you the the pounds should go on the bottom of a fraction (ratio, division)

see image. Divide to find the answer.

5 0
2 years ago
If a data set has only 1 outlier which value will always change when the outlier is excluded
blagie [28]

The median may stay the same.

The range will always change.

I dont think the last 2 will always change.

7 0
3 years ago
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