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Alexxx [7]
3 years ago
6

A soccer team played 25 games last season. They won 16 games, lost 5 games, and tied the rest.

Mathematics
1 answer:
goldenfox [79]3 years ago
6 0

Answer:

16% or 4/25

Step-by-step explanation:

16 + 5 = 21

25 - 21 = 4

4/25 = 16%

This is right because 21/25 is 84% and 84% + 16% = 100%

You might be interested in
What is 593,204 rounded to the nearest hundred thousand​
Alina [70]

Answer:

the answer is 600,000

Step-by-step explanation:

the 9 in the ten thousandth place gets rounded hire to 600,000

5 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
3 years ago
I need help I been asking for hours pls help
blsea [12.9K]

Answer:

419 ft

Step-by-step explanation:

1063 ft is about 324002.4 mm

324002.4/477 to get the scale ratio. Which is 679.25:1

I am halfway through the problem and notice I should have converted mm to ft and not the other way around. It gives the same answer it just takes an extra step.

188*679.25=127699mm for one side.

Convert that back to ft and you get 418.959 which would just be 419 ft

6 0
3 years ago
Read 2 more answers
1st Coordinate Point: (1.4)
snow_tiger [21]
Yea thats the coordinate plane good job
5 0
3 years ago
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