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postnew [5]
3 years ago
6

Please help!!! Will mark!!

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0
X^2+5x+6=0

x^2+2x+3x+6=0

x(x+2)+3(x+2)=0

(x+3)(x+2)=0

So the roots, zeros, or points where the graph touch the x-axis are when x=-2 and -3.


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Pleeaaassseeeees help,
sattari [20]

Hey there!

Since you probably have better things to do, your answer would be A: π(3)²

To back up my answer, the formula to find the area of a circle is π · R² where R = Radius. In that formula then, you just plug everything in. Since the radius is 3, you would put 3 into the "( )". Finally, just plug the rest of the equation in!

<em>I'm open to any question or comment!</em>

<em>God Bless!</em>

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5 0
3 years ago
I need help please, also if you could put the steps in and check that would be great. Also whoever does gets brainliest
denis23 [38]

Answer:  #7 is A and #8 is D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
50 POINTS + BRAINLIEST
Vedmedyk [2.9K]
X + 2y = 6
2y = -x + 6
  y = -1/2 x + 3 so slope = -1/2

parallel lines  has same slope = -1/2
perpendicular lines slope is opposite and reciprocal so slope = 2  
if slope not equal either -1/2 or 2 then neither.

y = -1/2 x - 5 ....m= - 1/2....  parallel

-2x + y = -4
          y = 2x - 4...m = 2 ....perpendicular

-x + 2y = 2
2y = x + 2
y = 1/2 x + 1 ...m = 1/2 ...neither

x + 2y = -2
2y = -x - 2
 y = -1/2 x - 1 ...m = -1/2 .....parallel

hope it helps
3 0
3 years ago
Read 2 more answers
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