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elena-14-01-66 [18.8K]
3 years ago
13

Factor 10x^3 8x^2 - 6x. ( a.2x(5x 4x - 3) ( b.2x(5x 4x^2- 3) ( c.2x(5x^2 4x - 3)

Mathematics
1 answer:
Semmy [17]3 years ago
4 0
You have to look at the equation and find a common factor bettween all parts. SO, we see they all have an x, so that is the first thing you can factor out. They also have 
2x(5x2 4x -3) C

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-4x + 2x + 3x + 8<br> Asap
Talja [164]

Answer:

x + 8

Step-by-step explanation:

1. To simplify this expression, we have to combine like terms.

  • (-4x + 2x + 3x) + (8)
  • (-2x + 3x) + (8)
  • x + 8

Therefore, the answer is x + 8.

4 0
2 years ago
Can someone help i know you looking
svp [43]

Answer:

A

Step-by-step explanation:

We know a number is an expression when it is:

1) NOT greater/ less than something else

2) NOT equal/ not equal to something else

The only answer choice that satisfies the above is A.

3 0
2 years ago
BRAINLIEST if right!
Brilliant_brown [7]
Y=-1/3x-1.
Hope this helps!
5 0
2 years ago
24% of students buy there lunch, 190 students bring their lunch from home. How many students are there in total
miv72 [106K]

so we know that 24% of the students buy their lunch at the cafeteria, and 190 students brownbag.

well, 100% - 24% = 76%, so the remainder of the students, the one that is not part of the 24% is 76%, and we know that's 190 of them.

since 190 is 76%, how much is the 24%?


\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 190&76\\ x&24 \end{array}\implies \cfrac{190}{x}=\cfrac{76}{24}\implies 4560=76x \\\\\\ \cfrac{4560}{76}=x\implies 60=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{total amount of students}}{190+60\implies 250}

6 0
3 years ago
Read 2 more answers
Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (assume that
Lilit [14]
Your sequence
  -8, 16/3, -32/9, 64/27
is a geometric sequence with first term -8 and common ratio
  (16/3)/(-8) = (-32/9)/(16/3) = -2/3

The general term an of a geometric sequence with first term a1 and ratio r is given by
  an = a1·r^(n-1)
For your sequence, this is
  an = -8·(-2/3)^(n-1)
6 0
3 years ago
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