Answer:
C code
Explanation:
#include <stdio.h>
void histrogram(int counters[])
{
int i,j;
int count;
for(i=0;i<26;i++)
{
count=counters[i];
printf("%c ",i+97);
for(j=0;j<count;j++)
{
printf("="); //= is used
}
printf("\n");
}
}
int main()
{
FILE* fp;
int i;
int arr[26];
char c;
int val;
// Open the file
fp = fopen("story.txt", "r");
if (fp == NULL) {
printf("Could not open file ");
return 0;
}
else
{
for(i=0;i<26;i++)
arr[i]=0;
for (c = getc(fp); c != EOF; c = getc(fp))
{
if(c>='a' && c<='z')
{
val = c-97;
//printf("%d ",val);
arr[val]++;
}
}
histrogram(arr);
}
}
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Answer:
if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.
When this case would appear, one thing that I would do personally would first, go to the settings, in then, after having this done, I would then "scroll down" to where ti would say "restore (uefi/bios) files, and from there, you would get every value that would would have from the beginning in your chip.
And also, what is truly unique would be the fact that you would be able to choose the "restore point" that you would like for it to appear.