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3 years ago

3

For what value of x does 64 Superscript 3 x Baseline = 512 Superscript 2 x + 12?

1 answer:

faust18 [17]3 years ago

4 0

Answer:

No solution.

Step-by-step explanation:

We are given that $(64)^{3x} = (512)^{(2x + 12)}$ and we have to solve this equation for x.

Now, 64 = $2^{6}$ and 512 = $2^{9}$

Therefore, $(2^{6} )^{3x} = (2^{9} )^{(2x + 12)}$ {Since $(x^{a} )^{b} = x^{ab}$ }

⇒ $2^{6 \times 3x} = 2^{9 \times (2x + 12)}$

⇒ $2^{18x} = 2^{18x + 108}$

Comparing the power of the same base, we get

18x = 18x + 108

Now, since 18x cancels from both the sides so, x has no solution. (Answer)

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Answer:

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Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

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(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

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Step-by-step explanation:

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