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4 years ago

Differentiate between heat and temperature

1 answer:

3 0

Often we think that heat and temperature are the same thing. ... Heat and temperature are related to each other, but are different concepts. Heat is the total energy of molecular motion in a substance while temperature is a measure of the average energy of molecular motion in a substance.

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Consider a 200 g sample of U-238 with decay constant 2.951x10^-16 min^1. Approximately how many disintegrations will occur per m

slamgirl [31]

Answer:

The disintegrations is $5.902\times10^{-17}\ decay /min$ .

Explanation:

Given that,

Weight of sample = 200 g

Decay constant $\lambda=2.951\times10^{-16}\ min^{-1}$

We need to calculate the disintegrations

Using formula of disintegrations

$\dfrac{dN}{dt}=\lambda N$

Where, $\lambda$ = decay constant

N = number of atoms present at time t

Put the value into the formula

$\dfrac{dN}{dt}=2.951\times10^{-16}\times200\times10^{-3}$

$\dfrac{dN}{dt}=5.902\times10^{-17}\ decay /min$

Hence, The disintegrations is $5.902\times10^{-17}\ decay /min$ .

7 0

4 years ago

At what altitude should a satellite be placed into circular orbit so that its orbital period is 48.0 hours? The mass of the eart

sveticcg [70]

Answer:

$60.689\times 10^6\ m$

Explanation:

Given:

Mass of Earth (M) = $5.976\times 10^{24}\ kg$

Radius of Earth (R) = $6.378\times 10^{6}\ m$

Time period of the satellite (T) = 48.0 hours

Converting time period from hours to seconds using the conversion factor, we get:

1 hour = 3600 s

So, 48.0 hours = 48.0 × 3600 = 172800 s

Let the distance of the satellite's orbit from Earth's center be 'r'.

We know that, the time period of the circular orbit is given by the formula:

$T=2\pi\sqrt{\frac{r^3}{GM}}$

Where, 'G' is the universal gravitational constant = $6.674\times 10^{-11}\ m^3kg^{-1}s^{-2}$

Rewriting in terms of 'r', we get:

$\frac{T}{2\pi}=\sqrt{\frac{r^3}{GM}}$

Squaring both sides, we get:

$(\dfrac{T}{2\pi})^2=\dfrac{r^3}{GM}\\\\\\r^3=\dfrac{GMT^2}{4\pi^2}\\\\\\r=\sqrt[3]{\dfrac{GMT^2}{4\pi^2}}$

Plug in the given values and solve for 'r'. This gives,

$r=\sqrt[3]{\dfrac{6.674\times 10^{-11}\times 5.976\times 10^{24}\times (172800)^2}{4\pi^2}} \\\\\\r=67.067\times 10^{6}\ m$

Now, altitude is measured from the surface of Earth. So, the altitude of the satellite's orbit is given by subtracting the radius of Earth from the total radial distance.

So, altitude (h) = Total radial distance (r) - Earth's radius (R)

$h=(67.067-6.378)\times 10^{6}\ m\\\\h=60.689\times 10^{6}\ m$

Therefore, the satellite's orbit must be placed at an altitude of $60.689\times 10^6\ m$

7 0

3 years ago

How many earth's are there in the universe??

loris [4]

Just one the earth is the only one like it it's completely unique

8 0

3 years ago

What is the wavelength of the sound wave that reaches your ear in a 20∘c room?

BaLLatris [955]

Missing text in the problem (found on internet):
"<span>A 70 cm -long steel string with a linear density of 1.0 g/m is under 200 N tension. It is plucked and vibrates at its fundamental frequency"

Solution:
The frequency of the sound wave along the string is given by
</span> $f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
<span>where L=70 cm=0.7 m is the length of the string, T=200 N its tension and </span> $\mu = 1g/m =0.001 kg/m$ is the linear density. Using these values in the formula, we find
$f=319.4 Hz$

4 0

3 years ago

A 4.76 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

Romashka-Z-Leto [24]

Answer:

The magnitude of the force is 64.634 newtons.

Explanation:

According to the statement, the crate is a constant mass system, whose upward force is described by the following expression:

$F(t) = m\cdot \ddot{y} (t)$ (1)