Question

Consider a 200 g sample of U-238 with decay constant 2.951x10^-16 min^1. Approximately how many disintegrations will occur per minute?

Answer 1

Answer:

The disintegrations is $5.902\times10^{-17}\ decay /min$.

Explanation:

Given that,

Weight of sample = 200 g

Decay constant $\lambda=2.951\times10^{-16}\ min^{-1}$

We need to calculate the disintegrations

Using formula of disintegrations

$\dfrac{dN}{dt}=\lambda N$

Where, $\lambda$ = decay constant

N = number of atoms present at time t

Put the value into the formula

$\dfrac{dN}{dt}=2.951\times10^{-16}\times200\times10^{-3}$

$\dfrac{dN}{dt}=5.902\times10^{-17}\ decay /min$

Hence, The disintegrations is $5.902\times10^{-17}\ decay /min$.